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3 years ago

Factor the following by using quadratic formula plz y=14x^2+12x+9

Mathematics

1 answer:

Scorpion4ik [409]3 years ago

5 0

Answer: 3 you are welcome :)

Step-by-step explanation: Eden h toy it right

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What does this mean ---->> 9e+10 please explain the answer

GenaCL600 [577]

This expression can't be solved because we don't know the value of e. Basically what this means is that e, an unknown number, is first being multiplied by 9, and it is then added by 10. You will just leave it as it is.

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3 years ago

F(x) = -x² - 7x - 5 Find f(-5)

irga5000 [103]

Answer:

Step-by-step explanation:

f(-5)=-(-5)^2 - 7(-5) - 5

f(-5)= -25 +35 - 5

f(-5) = -25 +30

f(-5) = 5

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2 years ago

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At which value in the domain does f(x) = 0? 2 2 4

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Step-by-step explanation:

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3 years ago

To round the number to the hundredths place, what should be done first?

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Step-by-step explanation:

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3 years ago

Graph f(x) =-2x^+16x-30 by factoring to find the solutions, then find the coordinates of the vertex, and the axis of symmetry. I

fredd [130]

Answer:

Observe attached image

Function zeros:

(3, 0), (5, 0)

Vertex:

(4, 2)

Axis of symmetry:

 $x =4$ 

Step-by-step explanation:

First factorize the function

$f (x) = -2x ^ 2 + 16x-30$

Take -2 as a common factor.

$-2(x ^ 2 -8x +15)$

Now factor the expression $x ^ 2 -8x +15$

You must find two numbers that when you add them, obtain the result -8 and multiplying those numbers results in 15.

These numbers are -5 and -3

Then we can factor the expression in the following way:

$f (x) = -2(x-5)(x-3)$

The quadratic function cuts the x-axis at x = 3 and at x = 5.

Now we find the coordinates of the vertex.

For a function of the form $ax ^ 2 + bx + c$ the x coordinate of its vertex is:

$x = \frac{-b}{2a}$

In the function $f (x) = -2x ^ 2 + 16x-30$

$a = -2\\b = 16\\c = 30$

Then the vertice is:

$x = \frac{-16}{2(-2)}\\\\x = 4$

The y coordinate of the symmetry axis is

$y = f (4) = -2 (4) ^ 2 +16 (4) -30\\\\y = 2$

The axis of symmetry is a vertical line that cuts the parabola in two equal halves. This axis of symmetry always passes through the vertex.

Then the axis of symmetry is the line

$x = 4$

The solutions and the vertice written as ordered pairs are:

Function zeros:

(3, 0), (5, 0)

Vertex:

(4, 2)

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3 years ago