Here is how to work it with long division.
2sin^2 θ + sin θ - 1 = 0
2sin^2 θ + 2sin θ - sin θ - 1 = 0
2sin θ(sin θ + 1) - 1(sin θ + 1) = 0
(2sin θ - 1)(sin θ + 1) = 0
2sin θ - 1 = 0 or sin θ + 1 = 0
sin θ = 1/2 or sin θ = -1
The two values of sin θ are 1/2 and -1
the answer is C.12.1 units
The answer is option B. Hope this helps:)
Answer:
Step-by-step explanation:
