Question 5<br> What is the area of the figure below?<br> 4 cm<br> 5 cm<br> 3 cm<br> 5 cm

There are 10 men and 14 women in.Kthleen's math class.what is the ratio of women to the total number of students in the class?

ahrayia [7]

The ratio can be determined as,

$\begin{gathered} \text{Ratio}=\frac{14}{10+14} \\ =\frac{14}{24} \\ =\frac{7}{12} \end{gathered}$

Thus, the requried ratio is 7:12.

3 0

1 year ago

Juanita is watering her lawn using the water stored in her rainwater tank the water in the tank drops 1/3 inch every 10 minutes

Ilya [14]

<span>Juanita is watering her lawn using the water that is stored by rainwater.
=> the water in the tank drops 1/3 inch in every 10 minutes she waters.
=> The tanks water level is 4 feet.
Question : Number of days can Juanita waters is she waters 15 minutes per day.
=> 4 feet is the total amount of water = 1 ft = 12 inches
=> 48 inches in total
=> 1/3 inch is used every 10 minutes = 0.33 inches
=> she waters 15 minutes per day = 0.495 inches in every 15 minutes
Solution
=> 48 inches / 0.495 inches per day
=> 96.97
So Juanita can use all the water in water tank for approximately 97 days.</span>

8 0

3 years ago

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What is the geometric mean of 12 and 47

aev [14]

Answer:

29.5 or 30 (rounded)

Step-by-step explanation:

Add 12 and 47 together and divide by 2 because there are 2 numbers.

3 0

2 years ago

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Holli's house is located at (−1, 4). She can walk in a straight line to get to Jedd's house. A fast food restaurant is located a

mojhsa [17]

<h2>Answer:</h2>

The coordinate of Jedd's house is:

(-7,-2)

<h2>Step-by-step explanation:</h2>

We know that if a Point P(a,b) partitions the line joining the point (x,y) and (x',y') in the ratio m:n

Then the coordinates of the point P is given by:

$a=\dfrac{mx'+nx}{m+n},\ b=\dfrac{my'+ny}{m+n}$

Here m:n=1:2

and (a,b)=(-3,2) i.e. location of the food restaurant.

and

(x,y)=(-1,4) i.e. location of Holli's house.

and (x',y') is the location of Jedd's house.

Hence, we have:

$-3=\dfrac{1\times x'+2\times (-1)}{1+2}\ and\ 2=\dfrac{1\times y'+2\times 4}{1+2}\\\\i.e.\\\\-3=\dfrac{x'-2}{3}\ and\ 2=\dfrac{y'+8}{3}\\\\i.e.\\\\-3\times 3=x'-2\ and\ 2\times 3=y'+8\\\\i.e.\\\\-9=x'-2\ and\ 6=y'+8\\\\i.e.\\\\x'=-9+2\ and\ y'=6-8\\\\i.e.\\\\x'=-7\ and\ y'=-2$