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Yanka [14]
3 years ago
5

It costs James an initial $7 fee to ride a taxi. Plus 6$ a minute. He ends up paying

Mathematics
1 answer:
malfutka [58]3 years ago
5 0

Answer:

$78

Step-by-step explanation:

Can i be brain list

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  • the plot is 5 and -4 I think
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There are 24 hours in a day and scientists tell us that we should sleep for 3/8 of the day how much time should we spend sleepin
Katyanochek1 [597]

Answer:

9

Step-by-step explanation:

3/8 × 24

= 3 × 3

= 9

9 Hours

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3 years ago
A water truck is filling a swimming pool. The equation that represents this
Luda [366]

Answer:

  a. false

  b. true

  c. true

  d. true

  e. false

Step-by-step explanation:

a. False. The "unit rate" is 19.75 gallons per minute. The "unit" of a "unit rate" is in the denominator. Here, the denominator of the rate is 1 minute.

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b. True. A graph of a proportional relationship is a straight line through the origin.

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c. True. In 5 minutes, the water in the pool will increase by 98.75 gallons, about 100 gallons.

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d. True. The ratio of a y-value to an x-value will always be 19.75. That is the meaning of this proportional relationship.

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e. False. The points (8, 158) or (7.5949, 150) will be on the graph. The point (8, 150) will not.

8 0
3 years ago
Some please help it urgent
Phoenix [80]

Answer: y axis = 20 x axis = 430

Step-by-step explanation: YOU´RE STUPID

8 0
3 years ago
Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,
sweet [91]

Answer:

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

f'' = x - \frac{3}{2}

f' = \int {\left(x-\frac{3}{2}\right) } \, dx

f' = \int {x} \, dx -\frac{3}{2}\int \, dx

f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C, where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative (f'(4) = 1):

1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C

C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)

C = -1

The first derivative is y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1, and the particular solution is found by integrating one more time and using the initial condition (f(0) = 0):

y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1  \right)} \, dx

y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx

y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C

C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0

C = 0

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

5 0
4 years ago
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