All categories

3 years ago

I need help with both of these if you know any of them them helppp me pls will give 20 points

Mathematics

1 answer:

Aliun [14]3 years ago

4 0

Answer:

1) B. similar

2) D. (4, 2)

Step-by-step explanation:

When a figure is dilated, the shapes will be similar. Reflected is another transformation so that's wrong. Same size and congruent is wrong since that would have to make the dilated size equal which can't since it's contradicting.

B: (4, -2)

Reflection across the x-axis:

(x, y) → (x, -y)

(4, -2) → (x, -y)

(4, 2)

You might be interested in

Which statment is true

Paraphin [41]

I think hamburger and French fries

6 0

3 years ago

The amount Kenyon earns on the sale of a car can be represented by the equation E (p) = 250 +0.02p where E(p) represents the tot

kap26 [50]

Answer:

1) His total commission is $1,234.3

2) The purchase of the car is $24,790.

Step-by-step explanation:

1) 21640*0.02= 432.8+ 250= 682.8

15075*0.02= 301.5+ 250= 551.5

682.8+ 551.5= 1,234.3

2) 745.8- 250= 495.8/ 0.02= 24,790

5 0

2 years ago

Read 2 more answers

High population density can cause increased competition for resources such as food or shelter, while a low population density ca

krek1111 [17]

Answer:

The region with the highest population density is Binky Lee

The region with the lowest population density is Cheslen

Step-by-step explanation:

we know that

The population density is the number of people per unit of area

Find out the population density for each region

Bear Creek

$\frac{462}{112}= 3.70\ people/acre$

Binky Lee

$\frac{12,624}{3,412}= 4.13\ people/acre$

Cheslen

$\frac{3,537}{1,263}= 2.80\ people/acre$

Crow's Nest

$\frac{2,142}{612}= 3.5\ people/acre$

Cheslen < Crow's Nest < Bear Creek < Binky Lee

therefore

The region with the highest population density is Binky Lee

The region with the lowest population density is Cheslen

4 0

3 years ago

Read 2 more answers

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

2 years ago

Tell whether the lines through the given points are parallel, perpendicular, or neither. (-3,1), (1,9), (-2-9), (-1,-7)

Brrunno [24]

Answer:

parallel

Step-by-step explanation:

all the details are in the attached picture.

4 0

3 years ago