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3 years ago

Could someone please help with this math problem??!

Mathematics

1 answer:

slavikrds [6]3 years ago

3 0

I agree with this person that will be a good use

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A group of 15 friends take a trip to a water park. The total price of the trip is $599.85 before any discounts. The total price

Citrus2011 [14]

Answer:10

Step-by-step explanation:

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3 years ago

Practicing Function Inverses, find values a,b,c,d,e <br> 50 Points = 25 points <br> Thank you.

o-na [289]

Answer:

a = -3.8

b = -2.6

c = 1.7

d = 4.4

e = 1.0

Step-by-step explanation:

Inverse just means that the x- and y-values are reversed. Notice how I didn't need to do any math to fill in the blanks; all the points are already given!

Please mark as Brainliest! :)

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3 years ago

Please help me solve thisss

Lorico [155]

The Vertical angle for <HKJ is <OKL or #12

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3 years ago

Your family is installing a new square pool in the backyard. The existing patio has a side length of 8 feet. How much of the pat

trasher [3.6K]

The question is an illustration of perimeters.

The amount of patio to remove to install the pool is 8 feet.

From the question, we have:

$\mathbf{Length\ of\ the\ pool = 8}$

$\mathbf{Length\ of\ walkway = 1}$

The perimeter of the patio is:

$\mathbf{P_p = 4 \times Length\ of\ the\ pool}$

$\mathbf{P_p = 4 \times 8}$

$\mathbf{P_p = 32}$

A 1ft walkway means that;

1ft would be subtracted from both sides of the patio before installing the pool

So, the perimeter of the patio in terms of the length of the pool is:

$\mathbf{P_p = 4 \times (x +2)}$

Equate both expressions

$\mathbf{P_p = P_p}$

$\mathbf{4 \times (x +2) = 32}$

Divide both sides by 4

$\mathbf{x +2 = 8}$

Subtract 2 from both sides

$\mathbf{x = 6}$

So, the perimeter of the pool is:

$\mathbf{P_{pool} = 4 \times 6}$

$\mathbf{P_{pool} = 24}$

The amount of patio to remove is:

$\mathbf{Amount = P_p - P_{pool}}$

So, we have:

$\mathbf{Amount = 32 - 24}$

$\mathbf{Amount = 8}$

Hence, 8ft of the patio would be removed to install the pool

<em>See attachment for illustration</em>