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goldfiish [28.3K]
3 years ago
5

What is the greatest common monomial factor of 6m3x4 + 30m5y2 + 45m3x6y2? 6m5x6y2 3m3 6m3 3m5x6y2

Mathematics
2 answers:
Digiron [165]3 years ago
8 0
I’d say 6 but I could be wrong
alex41 [277]3 years ago
7 0

Answer:

3m³

Step-by-step explanation:

The leading coefficiets, 6, 30 and 45 are all divisible by 3

m is the only variable present in all three terms.

m³ is a factor of m⁵

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May someone help me out with this
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Solve for x (13x + 2) (5x - 7) (3x - 4)<br><br><br> Thank you
Law Incorporation [45]

\huge \bf༆ Answer ༄

As we know, sum of interior angles of a triangle is 180°

that is ~

  • \sf13x + 2 + 5x - 7 + 3x - 4 = 180

  • \sf21x  - 9 = 180

  • \sf21x = 180 + 9

  • \sf x =  \dfrac{189}{21}

  • \sf x = 9 \degree

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3 years ago
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The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a
liubo4ka [24]

Answer:

(x,y,z)=(1477, 1464, 1437)

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>
  • Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
  • Mr.A earns Rs6000

So, the equation would be

3x  +  5y - 4z = 6000

<h3>Case-2:</h3>
  • Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
  • Mr B neither lose nor gain meaning he has made 0₹

hence,

2x   - 3y  +  z = 0

<h3>Case-3:</h3>
  • Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
  • Mr.C earns 13000₹

therefore,

- x    + 4y  +  6z = 13000

Thus our system of equations is

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\end{cases}\\\begin{cases}2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

Now solve the equation accordingly:

\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}

Solving the equation for x and y yields:

\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

\implies z= \dfrac{217000}{151}

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

6 0
2 years ago
Write 10^4 as a product of the same factor
galina1969 [7]

Answer:

1000?

10x10x10x10?

don't really get it, but prob the second one.

4 0
3 years ago
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