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goldfiish [28.3K]
3 years ago
5

What is the greatest common monomial factor of 6m3x4 + 30m5y2 + 45m3x6y2? 6m5x6y2 3m3 6m3 3m5x6y2

Mathematics
2 answers:
Digiron [165]3 years ago
8 0
I’d say 6 but I could be wrong
alex41 [277]3 years ago
7 0

Answer:

3m³

Step-by-step explanation:

The leading coefficiets, 6, 30 and 45 are all divisible by 3

m is the only variable present in all three terms.

m³ is a factor of m⁵

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Three men and seven women are waiting to be interviewed for jobs. If they are all selected in random​ order, find the probabilit
sammy [17]

Answer:

1/50

Step-by-step explanation:

Given that:

  • Three men: 3
  • Seven women = 7
  • Total number of people: 7+3 =10

We need to find the probability that no man will be interviewed until at least two women have been interviewed. So there are two possible probabilities are:

1. One man and two women => P(1 man and 2 women) = 3/10*2/9 = 1/15

2. Three women => P(3 women) = 3/10

Hence, the probability in this situation is: 1/15*3/10 = 1/50

8 0
2 years ago
Inez has 27 basketball cards and 45 baseball cards in her card collection. What time is the ratio of Inez’s baseball cards to he
lisov135 [29]
The ratio is 45:27= 5:3
8 0
2 years ago
A swimming pool has a capacity of 2,500 gallons of water. The output of a hose is 25 gallon per minute. How much time would it t
g100num [7]

Answer:

  • 100 minutes

Solution:

<u>We know that:</u>

  • Capacity = 2,500 gallons
  • Hose = 25 gallons/minute

Solution:

  • 25 gallons = 1 minute
  • => 25x gallons = x minutes = 2500 gallons
  • => 25x = 2500
  • => x = 100 minutes

Hence, it will take 100 minutes to fill the pool.

4 0
2 years ago
Two particles are fixed to an x axis: particle 1 of charge -1.00 x 10-7 C is at the origin and particle 2 of charge +1.00 x 10-7
r-ruslan [8.4K]
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint. 

The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
6 0
3 years ago
Find the simple interest earned on $2600 invested for 3 years at 12% per annum​
Aleks04 [339]

Answer:

$936

Step-by-step explanation:

Simple interest is money you can earn by initially investing some money (a.k.a the principal). In return, a percentage (a.k.a the interest) of the initial money invested is added to the principal, this is what makes your initial investment grow.

The equation for simple interest is:

I = P x r x t

P = Principal, $2600

r = interest rate, 12%

t = time involved, 3 years

Fill in the values:

2600 × 0.12 × 3 = $936.00

5 0
3 years ago
Read 2 more answers
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