I guess try A I really don’t know
<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
Answer:
The area of sail A is One-fourth the area of sail B.
Step-by-step explanation:
Answer =
E = 1/2 = 0.500
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Now you need to rearrange the problem ( common sense :) :
1/2 * e - (1/4 ) = 0 | Now we need to Simplify 1/4 : 1/2 * e - 1/4 = 0
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Now we need to simplify 1/2 : 1/2 * e - 1/4 = 0
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What are there denominators??? = 2 and 4 ,,,,,, DUH . LOL
The lease common multiple is 4.
Now divide 1/2 by e which is 1/2 = 0.500
i hope this helps you a lot
I think it is random sampling because he picked one out of every 3 girls. Therefore, he picked at random.
Hope that helped!
Mandy Woodland