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Simplify 7(2x+y)+6(×+5y)

iris [78.8K]

Simplify, 7(2x+y)+6(x+5y).

a: 20x+37y

(7 • (2x + y)) + 6 • (x + 5y)

Step 2 :

Equation at the end of step 2 :

7 • (2x + y) + 6 • (x + 5y)

Step 3 :

Final result :

Thanks,

Deku ❤

4 0

3 years ago

Which expressions are equivalent to the given expression?

expeople1 [14]

Answer:

It is the 2nd answer choice 4 check 5

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Hose is 32 feet long 32 feet long it needs to be cut into pieces equaling 5’3” How many whole pieces can be cut into how many wh

luda_lava [24]

Answer:

6

Step-by-step explanation:

Question tests the ability to get quotient

Here, 32 ft is divided by 5’3”

Normally, ft is denoted by ' while inches is denoted by ". So we divide 32 ft by 5ft and 3 inches

First, we convert dimensions into similar units. To convert 5’3” to ft, we divide 3” by 12 hence 3÷12=0.25'

The total is now 5.25'

Now

32'÷5.25'=6.1538461538461

This means, we shall obtain 6 whole pieces with some remainder. Since the question needs the whole pieces only, then the answer is 6

3 0

2 years ago

Answer if you want, 10 points

rjkz [21]

Answer:

hi

Step-by-step explanation:

for example

$\frac{8}{4} = 2 \\ \\ 1 \times \frac{4}{5} = \frac{9}{5}$

in the second one you should multiple 5 and 1 then add 4

8 0

3 years ago

A research study investigated differences between male and female students. Based on the study results, we can assume the popula

garri49 [273]

Using the normal distribution and the central limit theorem, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of $\mu = 3.5$ .

The standard deviation is of $\sigma = 0.5$ .

Sample of 100, hence $n = 100, s = \frac{0.5}{\sqrt{100}} = 0.05$

The interval that contains 95.44% of the sample means for male students is between Z = -2 and Z = 2, as the subtraction of their p-values is 0.9544, hence:

Z = -2:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$