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3 years ago

Question 1 (1 point)

Mathematics

2 answers:

Mariulka [41]3 years ago

8 0

Answer:

YOOOOOOO

Step-by-step explanation:

What answer did you get?

Soloha48 [4]3 years ago

5 0

Answer:

The points that lie in the solution set of following system of inequalities are:

Option A (1,-5) and Option C (5,1)

Step-by-step explanation:

We need to find the points that lie in the solution set to the following system of inequalities

$y$

We will check each option to identify if they satisfy the given set of inequalities or net.

Option A (1,-5)

We have x=1, y=-5

Putting values and checking

$\\y$

So, Option A is correct as both values satisfy the given set of equations

Option B (1,5)

We have x=1, y=5

Putting values and checking

$y$

So, Option B is not correct as both values doesn't satisfy the given set of equations

Option C (5,1)

We have x=5, y=1

Putting values and checking

$y$

So, Option C is correct as both values satisfy the given set of equations

Option D (-1,5)

We have x=-1, y=5

putting values and checking

$y$

So, Option D is not correct as both values doesn't satisfy the given set of equations

The points that lie in the solution set of following system of inequalities are:

Option A (1,-5) and Option C (5,1)

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Consider the square root function f(x) = sqrt x + 2 + 1 to complete the table of values below. find each missing value and then

Scrat [10]

Given the function :

$f(x)=\sqrt[]{x+2}+1$

We need to find each missing value

Given x = -3 , -2 , -1 , 2 , 7

So, substitute with each value of x to find the corresponding value of f(x)

$x=-3\rightarrow f(x)=\sqrt[]{-3+2}+1=\sqrt[]{-1}+1$

So, there is no value for f(x) at x = -3 (the function undefined because the square root of -1)

$\begin{gathered} x=-2\rightarrow f(x)=\sqrt[]{-2+2}+1=\sqrt[]{0}+1=0+1=1 \\ \\ x=-1\rightarrow f(x)=\sqrt[]{-1+2}+1=\sqrt[]{1}+1=1+1=2 \\ \\ x=2\rightarrow f(x)=\sqrt[]{2+2}+1=\sqrt[]{4}+1=2+1=3 \\ \\ x=7\rightarrow f(x)=\sqrt[]{7+2}+1=\sqrt[]{9}+1=3+1=4 \end{gathered}$

the graph of the function and the points will be as shown in the following image :