When we reject the null and the null is true, we have a made a type I error
The null hypothesis in statistics states that there is no difference between groups or no relationship between variables. It is one of two mutually exclusive hypotheses about a population in a hypothesis test.
null hypothesis is denoted as H₀
Reject the null hypothesis when the p-value is less than or equal to your significance level. Your sample data favor the alternative hypothesis, which suggests that the effect exists in the population. When you can reject the null hypothesis, your results are statistically significant.
when the p-value is greater than your significance level, you fail to reject the null hypothesis.
Sometimes , we reject our null hypothesis even when its true
there we made a type I error in hypothesis
To know more about null hypothesis here
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1.50s + 0.75f = 116.25
2f = s
1.50(2f) + 0.75f = 116.25
3f + 0.75f = 116.25
3.75f = 116.25
f = 116.25/3.75
f = 31...31 friday papers
2f = s
2(31) = s
62 = s <=== 62 sunday papers
L = 15
w = 12
h = 8
Surface Area = 2(lw + wh + lh)
S.A. = 2(15*12 + 12*8 + 15*8)
S.A. = 2(180 + 96 + 120)
S.A. = 2(396)
S.A. = 792 cm^2
Notice that
(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>
So we can add 1 to both sides of both equations, and we use the property above to get
<em>a</em> + <em>b</em> + <em>a b</em> = 76 ==> (1 + <em>a</em>)(1 + <em>b</em>) = 77
and
<em>c</em> + <em>d</em> + <em>c d</em> = 54 ==> (1 + <em>c</em>)(1 + <em>d</em>) = 55
Now, 77 = 7*11 and 55 = 5*11, so we get
<em>a</em> + 1 = 7 ==> <em>a</em> = 6
<em>b</em> + 1 = 11 ==> <em>b</em> = 10
(or the other way around, since the given relations are symmetric)
and
<em>c</em> + 1 = 5 ==> <em>c</em> = 4
<em>d</em> + 1 = 11 ==> <em>d</em> = 10
Now substitute these values into the desired quantity:
(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000
Answer:
Percent increase = 60%
Percent increase with baggage = 83%
Step-by-step explanation:
Given that:
Old price of the ticket = $210
New price of the ticket = $335
Increase amount =335-210 = $125
Percent increase = 
Percent increase = 
Percent increase = 59.52% = 60%
Additional charges = $125+$50 = $175
Percent increase = 
Percent increase = 83%
Hence,
Percent increase = 60%
Percent increase with baggage = 83%
