All categories

3 years ago

Please help answer the question in the picture

Mathematics

2 answers:

weeeeeb [17]3 years ago

5 0

Answer:

Step-by-step explanation:

All you to do is plug in the the given range [-2,0,5] in the x of your given function (y=-5x +4) and solve for each number.

musickatia [10]3 years ago

3 0

A in the answer for this question
Thank you

You might be interested in

The points P(2,3) , Q(-1,1) and R(5,-1) are the vertices of a triangle PQR.Find the equation of the altitude of the triangle PQR

vfiekz [6]

Answer:

$y = \frac{3}{4} x+ \frac{7}{4}$

Step-by-step explanation:

The slope of straight line PR where P(2,3) and R(5,-1) are two vertices of triangle PQR will be = $\frac{3-(-1)}{2-5} =-\frac{4}{3}$

Therefore, the slope of the altitude passing through Q(-1,1) will be $\frac{3}{4}$ {Since, the product of slopes of two perpendicular straight line is -1}

So, equation of the altitude is $y=\frac{3}{4} x + c$ where c is a constant.

Now, putting x = -1 and y = 1 in the above equation we get

$1 = -\frac{3}{4} + c$

⇒ $c=\frac{7}{4}$

Therefore, the equation of the altitude is $y = \frac{3}{4} x+ \frac{7}{4}$ (Answer)

6 0

3 years ago

Type the number to the left of the rational number in the box to the point it represents on the number

svlad2 [7]

Answer:

I put the numbers first because it was easier for me to do but if it confuses you I can redo it

1. C

2. D

3. F

4. B

5. E

6. A

7 0

2 years ago

Use separation of variables to solve dy dx − tan x = y2 tan x with y(0) = √3. Find the value of c in radians, not degrees

a_sh-v [17]

Answer:

$y(x)=tan(-log(cos(x))+\frac{\pi }{3} )$

Step-by-step explanation:

Rewrite the equation as:

$\frac{dy(x)}{dx}-tan(x)=y(x)^{2} *tan(x)$

Isolating $\frac{dy}{dx}$

$\frac{dy}{dx} =tan(x)+tan(x)*y^{2}$

Factor:

$\frac{dy}{dx} =tan(x)*(1+y^{2} )$

Dividing both sides by $(1+y^{2} )$ and multiplying them by $dx$

$\frac{dy}{1+y^{2} } =tan(x)dx$

Integrate both sides:

$\int\ \frac{dy}{1+y^{2} } = \int\ tan(x) dx$

Evaluate the integrals:

$arctan(y)=-log(cos(x))+C_1$

Solving for y:

$y(x)=tan(-log(cos(x))+C_1)$

Evaluating the initial condition:

$y(0)=\sqrt{3} =tan(-log(cos(0))+C_1)=tan(-log(1)+C_1)=tan(0+C_1)$

$\sqrt{3} =tan(C_1)\\arctan(\sqrt{3} )=C_1\\60=C_1$

Converting 60 degrees to radians:

$60degrees*\frac{\pi }{180degrees} =\frac{\pi }{3}$

Replacing $C_1$ in the diferential equation solution:

$y(x)=tan(-log(cos(x))+\frac{\pi }{3} )$

3 0

3 years ago

Are f and g inverses of each other? Support your response algebraically

NeTakaya

Answer:

see explanation

Step-by-step explanation:

If f(x) and g(x) are the inverses of each other, then

f(g(x)) = g(f(x)) = x

f(g(x)) = f(x - $\frac{1}{2}$ ) = x - $\frac{1}{2}$ + $\frac{1}{2}$ = x

g(f(x)) = g(x + $\frac{1}{2}$ ) = x + $\frac{1}{2}$ - $\frac{1}{2}$ = x

Hence f(x) and g(x) are the inverse of each other

4 0

3 years ago

WHICH TABLE IS A FUNCTION?<br> TABLE A<br> TABLE B<br> NEITHER<br> BOTH

Alexandra [31]

I believe it neither

3 0

3 years ago

Read 2 more answers

Please help answer the question in the picture ​

Please help answer the question in the picture