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WITCHER [35]
3 years ago
13

6. 4/5 x 5/6

Mathematics
1 answer:
fgiga [73]3 years ago
3 0

Answer:

6.  2/3

7.  5.67

8.  2.1

9. 5/12

10. 1/15

11. 1  1/2

12.  3/10

Step-by-step explanation:

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X^4/3-7x^2/3+10=0 what is x
MakcuM [25]
Solve for x:10 - (7 x^2)/3 + X^4/3 = 0
Subtract X^4/3 + 10 from both sides:-(7 x^2)/3 = -X^4/3 - 10
Multiply both sides by -3/7:x^2 = X^4/7 + 30/7
Take the square root of both sides:Answer:  x = sqrt(X^4/7 + 30/7) or x = -sqrt(X^4/7 + 30/7)
6 0
3 years ago
HELPPP PLSSSS THE PYTHAGOREAN THEOREM
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Answer:

Step-by-step explanation:

a²+b² = c² c is always the longest line thats opposite to the 90 degree angle

for 1

15² + b² = 17²

b² = 17² - 15²

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8 0
3 years ago
Please help me do this I don't understand: 5 - 3x + y +6
mafiozo [28]
I hope this helps you



5+6-3x+y


11-3x+y
4 0
3 years ago
Read 2 more answers
Prove that the points (3,3),(3,7) and (9,3) are the vertices of a right triangle
Alinara [238K]

The points (3,3), (3,7) and (9,3) do not form a right angled triangle

<em><u>Solution:</u></em>

Given vertices of triangle are (3, 3) , (3, 7) and (9, 3)

Let the triangle be ABC

Let the vertices be,

A = (3, 3)

B = (3, 7)

C = (9, 3)

For a triangle to be right angled triangle, it must obey Pythagoras theorem

Pythagorean theorem, states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

Therefore by above definition,

AC^2 = AB^2 + BC^2

Let us use the distance formula

D=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

<em><u>The distance between A and C is given as:</u></em>

\text{ Here } x_1 = 3 ; y_1 = 3 ; x_2 = 9 ; y_2 = 3

Therefore,

\begin{array}{l}{D=\sqrt{(9-3)^{2}+(3-3)^{2}}} \\\\{D=\sqrt{6^{2}+0}=\sqrt{36}=6}\end{array}

Thus length of AC is 6 units

<em><u>The distance between A and B is given as:</u></em>

\text{ Here } x_1 =3 ; y_1 = 3 ; x_2 = 3; y_2 = 7

\begin{array}{l}{D=\sqrt{(3-3)^{2}+(7-3)^{2}}} \\\\{D=\sqrt{0+4^{2}}=\sqrt{16}=4}\end{array}

<em><u>The distance between B and C is given as:</u></em>

\text{ Here } x_1 = 3 ; y_1 = 7 ; x_2 = 9 ; y_2 = 3

\begin{aligned}&D=\sqrt{(9-3)^{2}+(3-7)^{2}}\\\\&D=\sqrt{6^{2}+(-4)^{2}}=\sqrt{36+16}=\sqrt{52}\end{aligned}

Thus by Pythagorean theorem,

AC^2 = AB^2 + BC^2

Substituting the obtained values we get,

6^2 = 4^2 + (\sqrt{52})^2\\\\ 36 = 16 + 52\\\\36 \neq 68

Thus the vertices does not form a right angled triangle

8 0
4 years ago
A doctor put 3.09 ounces of vitamin pills into
VARVARA [1.3K]

Answer:

103 bottles you can just use a calculator for that

6 0
3 years ago
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