This is how you do it. Set two equations equal to each other then solve. Plug in x for each equation, find the answers. AC is the base because it is not congruent to any other side.
Answer:
it is a :) hope this helped :)
Step-by-step explanation:
First factor the numerator
b^2-6b+8/b-4 * b+8/b-2
u will get
(b-2)(b-4)/(b-4)*(b-2)*b+8
those will cancel out each other will left only
b+8<span />
The numbers DO differ by 10 if they are
- 1 and 11
- 2 and 12
- 3 and 13
- 4 and 14
- 5 and 15
Each outcome technically has two ways of occurring, but since we're taking two marbles at a time, that would be the same as saying, for instance, that drawing 1 and 11 is the same as drawing 11 and 1. We only count such an event once.
So the answer is (a) 5.
If you look from the points at angle 73, to 42, to 131, to z, the shape makes a quadrilateral.
Since the total of the interior angles in a quadrilateral add up to 360 you make an equation:
360 = 131 + 73 + 42 + 7 + x
Re-arrange the equation to get the x alone, by subtracting:
360 - 131 - 73 - 42 = x
114 = x
So x = 114 degrees<span />
