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Rina8888 [55]
3 years ago
10

What is f(g(x)) for x > 5?

Mathematics
2 answers:
torisob [31]3 years ago
6 0

ANSWER

f(g(x)) =4{x}^{2}  - 41x + 105

EXPLANATION

The given functions are:

f(x) = 4x -  \sqrt{x}

and

g(x) =  {(x - 5)}^{2}

To find

f(g(x)) = f( {(x - 5)}^{2} )

f(g(x)) =4 {(x - 5)}^{2}  -  \sqrt{{(x - 5)}^{2} }

We expand and simplify to obtain,

f(g(x)) =4 {( {x}^{2}  - 10x + 25)} -  (x - 5)

f(g(x)) =4{x}^{2}  - 40x + 100 -  x  +  5

Combine similar terms to get;

f(g(x)) =4{x}^{2}  - 41x + 105

The correct choice is B.

Amanda [17]3 years ago
4 0

f(g(x))  (you plug/substitute g(x) into x)

f(x) = 4x - √x

f(g(x)) = 4(g(x)) - √(g(x))      since g(x) = (x - 5)², you can do:

f(g(x)) = 4(x - 5)² - √(x - 5)²     The ² and √ cancel each other, leaving

f(g(x)) = 4(x - 5)² - (x - 5)      Next factor out (x - 5)² or (x - 5)(x - 5)

f(g(x)) = 4(x² - 10x + 25) - (x - 5)  Now distribute the 4 and the -

f(g(x)) = 4x² - 40x + 100 - x + 5   Simplify

f(g(x)) = 4x² - 41x + 105         Your answer is B

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