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aev [14]
3 years ago
3

A sum of money increased by its 0.05 in every 6 months after how long time the annual compound interest on Rs. 4000 will be Rs.

1324?​
Mathematics
1 answer:
Tanya [424]3 years ago
5 0

Answer:

3 x 2 = 6 years to get Rs. 1324

Step-by-step explanation:

This is a mathematical relationship that transcends currencies. In other words, it also applies to Dollars, Pounds and Yen.

“Annual compound interest” is a phrase of dubious meaning. The process is a “compound interest problem”, but the item I think you are looking for is simply the amount of interest.

Month 0: interest: 0 balance: 4,000

Month 6: interest; 200 balance: 4,200

Month 12: interest 210 balance: 4,410 12-month total interest: 410

Month 18: interest: 220.5 balance: 4,630.5 12-month total interest: 430.5

Month 24: interest: 231.525 balance: 4,862.025 12-month total interest: 452.025

Month 30: int: 243.10125 bal: 5,105.12625 12-month total int: 474.35125

Keep expanding this progression until the 12-month total interest meets or exceeds 1324, the answer will be the number of months in the last line.

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a^2+11a+30

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Rewrite 8x - 7 as the product of two factors
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2X + 6 = 2 * (X + 3)

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3 0
3 years ago
A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

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From the initial condition, ...

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So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

___

The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

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