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aev [14]
3 years ago
3

A sum of money increased by its 0.05 in every 6 months after how long time the annual compound interest on Rs. 4000 will be Rs.

1324?​
Mathematics
1 answer:
Tanya [424]3 years ago
5 0

Answer:

3 x 2 = 6 years to get Rs. 1324

Step-by-step explanation:

This is a mathematical relationship that transcends currencies. In other words, it also applies to Dollars, Pounds and Yen.

“Annual compound interest” is a phrase of dubious meaning. The process is a “compound interest problem”, but the item I think you are looking for is simply the amount of interest.

Month 0: interest: 0 balance: 4,000

Month 6: interest; 200 balance: 4,200

Month 12: interest 210 balance: 4,410 12-month total interest: 410

Month 18: interest: 220.5 balance: 4,630.5 12-month total interest: 430.5

Month 24: interest: 231.525 balance: 4,862.025 12-month total interest: 452.025

Month 30: int: 243.10125 bal: 5,105.12625 12-month total int: 474.35125

Keep expanding this progression until the 12-month total interest meets or exceeds 1324, the answer will be the number of months in the last line.

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Notación científica de 0,567
Phoenix [80]

Answer:

0,00567×10¹

Step-by-step explanation:

Para convertir a notación decimal:

0.00567×10¹

4 0
3 years ago
4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25
jarptica [38.1K]

Answer with explanation:

\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

 =e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}

Multiplying both sides by Integrating Factor  

x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0
3 years ago
The description below represents Function A and the table represents Function B: Function A The function is 2 more than 5 times
Vlad [161]

Answer:

The slope of Function A is greater than the slope of function B  while the y-intercept of Function  B is greater than the y-intercept of function A.

Step-by-step explanation:

Function A is f(x) = 5x + 2

The slope is 5 and the y-intercept is (0, 2).

Function B. The slope is  (5-2) / (0- -1) = 3.

also (8-5) / (1 - 0) = 3

The slope is 3.

The y-intercept is at (0, 5) because one point on the graph is (0, 5).

7 0
3 years ago
What is an equation of the line that is parallel to y=-4x - 5 and passes through the point (-2, 6)?
Alex73 [517]

Answer:

B.) y=-4x-2

Step-by-step explanation:

If the line is parallel, the slope is the same

y = -4x-5 has a slope of -4, so the new line has a slope of -4

We have a slope and a point, so we can use point slope form

y-y1 = m(x-x2)

y-6 = -4(x--2)

y-6 = -4(x+2)

Distribute

y-6 =-4x -8

Add 6 to each side

y-6+6 = -4x-8+6

y = -4x-2

3 0
3 years ago
2 people answer this so i can give one of you brainliest2 people answer this so i can give one of you brainliest2 people answer
Furkat [3]

Answer:

ummmmm ok u wanted someone to answer

Step-by-step explanation:

also do u have any song ideas

4 0
3 years ago
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