Answer:
0.0035289
Step-by-step explanation:
From the question;
mean annual salary = $63,500
n = sample size = 31
Standard deviation = $6,200
Firstly, we calculate the z-score of $60,500
Mathematically;
z-score = x-mean/SD/√n = (60500-63500)/6200/√(31) = -2.6941
So we want to find the probability that P(z < -2.6941)
We can get this from the standard normal table
P( z < -2.6941) = 0.0035289
Answer:
See below.
Step-by-step explanation:
6.) (5)/6 ≤ 1 (Yes)
7.) 1.4(11) > 16
15.4 > 16 (No)
8.) 11.1 + 9.8 ≥ 21.01
20.9 ≥ 21.01 (No)
9.) 2.5 < (90)/30
2.5 < 3 (Yes)
10.) 1/2 > 3(1/6)
1/2 > 1/2 (No)
11.) 2.16 ≥ 3(0.6) - 0.5
2.16 ≥ 1.8 - 0.5
2.16 ≥ 1.3 (Yes)
12.) x < 2 (x is less than 2.)
13.) x ≥ -1 (x is greater than or equal to -1.)
3x - 12
3(3x/3 - 12/3)
3(x - 4)
The answer is: 3(x - 4).
I've attached a plot of one such cross-section (orange) over the region in the x-y plane (blue), including the bounding curves (red). (I've set

for this example.)
The length of each cross section (the side lying in the base) has length determined by the horizontal distance

between the y-axis

and the curve

. In terms of

, this distance is

. The height of each cross section is twice the value of

, so the area of each rectangular cross section should be

.
This means the volume would be given by the integral