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2 years ago

I don't understand this, I have the answer but I don't know or how to explain my work.

Mathematics

2 answers:

svp [43]2 years ago

8 0

Answer:

Step-by-step explanation:

0.25 = 1/4 = 5/20

0.35 = 35/100 = 7/20

5/20 + 7/20 = 12/20 = 6/10 = 3/5

horrorfan [7]2 years ago

4 0

Answer:

Step-by-step explanation:

so first you would do 0.25+0.35= 0.6

now put 0.6 into a fraction= 6/10 because 6 is in the 10th place then simplify 6/10=3/5 which to find that you divide each side by 2

Hope This Helped!

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2 years ago

A sheet of paper is 8.25 inches wide by 11.3 inches long. What is the area of the front of the paper? 93.225 square inches 94.08

g100num [7]

Step-by-step explanation:

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2 years ago

The curved surface area of a right circular cylinder of height 14 cm is 88 cm2. find the diameter of the base of the cylinder

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2 cm

Step-by-step explanation:

h = 14 cm

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6 0

2 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

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2 years ago