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Nata [24]
3 years ago
10

Graph the line that passes through the points (9,-8) and (9,6) and determine the

Mathematics
1 answer:
avanturin [10]3 years ago
7 0

Answer:

<em>x = 9</em>

Step-by-step explanation:

The standard form of equation of a line is expressed as y = mx+c

m is the slope

c is the y intercept

Note that the line does not have a slope and the x intercept of the line is a point where the line cuts the x axis. Hence the equation of the line will be expressed as x = c where c is the x intercept;

<em>From the graph, the x intercept =9. Hence the equation of the given line is x = 9</em>

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A=755y/t^2 <br> Solve for y.
timofeeve [1]

Answer:

y = At²/755

Step-by-step explanation:

A = 755y/t²

multiply both sides by t²

At² = 755y

Divide both sides by 755

At²/755 = y

Flip

y = At²/755

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The product of c and 2 is greater than or equal to 20
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The product of c and 2 is greater than or equal to 20


c*2 >=20

divide by 2

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3 years ago
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3 years ago
What is the distance between parallel lines whose equations are y = 2x + 7 and y = 2x – 3?
malfutka [58]

Answer:

The distance is \sqrt{20} or 2\sqrt{5}.

Step-by-step explanation:

Slope of parallel: 2

Slope of perpendicular: -1/2

Pick a point for y =2x + 7. For example (0,7)

Use the perpendicular slope to get to the other line to find the other point of y=2x-3. Look at the screenshot...I got (4,5).

Distance formula \sqrt{(x_{2}-x_{1} )^{2}+(y_{2} -y_{1})^2   }

Insert (0,7) and (4,5)

\sqrt{(0-4)^{2}+(7-5)^2   } = \sqrt{(-4)^{2}+(2)^2   } = \sqrt{(16)+(4)}  } = \sqrt{20}  = 2\sqrt{5}

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