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3 years ago

The short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown

Mathematics

1 answer:

Brums [2.3K]3 years ago

8 0

Answer:

The first student is correct

Step-by-step explanation:

With the given information there is already 4 inches on the rectangle. 13 x2 = 26. 26+4=30. For student two if the unknown number was 10 it would not work because the longest side is 3 less then the unknown number. 10-3=7. 7x2=14. 14+4= 28<30

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2 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

The table summarizes the scoring of a football game between Team A and Team B. A touchdown (TD) is worth 6 points, a field goal

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If you would like to find the final score, you can do this using the following steps:

Team A: 6 points * 3 + 3 points * 2 + 2 points * 1 + 1 point * 0 = 6 * 3 + 3 * 2 + 2 * 1 + 1 * 0 = 18 + 6 + 2 + 0 = 26 points
Team B: 6 points * 4 + 3 points * 4 + 2 points * 1 + 1 point * 2 = 6 * 4 + 3 * 4 + 2 * 1 + 1 * 2 = 24 + 12 + 2 + 2 = 40 points

The final score of team A is 26 points and the final score of team B is 40 points.

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3 years ago