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igor_vitrenko [27]

3 years ago

12

The short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown

1 answer:

Brums [2.3K]3 years ago

8 0

Answer:

The first student is correct

Step-by-step explanation:

With the given information there is already 4 inches on the rectangle. 13 x2 = 26. 26+4=30. For student two if the unknown number was 10 it would not work because the longest side is 3 less then the unknown number. 10-3=7. 7x2=14. 14+4= 28<30

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Please help me idk this

Murljashka [212]

Answer:

5/7

Step-by-step explanation:

we find the greatest number that can be multiplied to get each number. it is 11. 11 goes into 55 5 times, and into 77 7 times therefore giving us 5/7

7 0

3 years ago

Which equation does the graph of the systems of equations solve? 2 linear graphs. They intersect at 1,4

Pepsi [2]

Answer:

See below.

Step-by-step explanation:

There is an infinite n umber of systems of equations that has (1, 4) as its solution. Are you given choices? Try x = 1 and y = 4 in each equation of the choices. The set of two equations that are true when those values of x and y are used is the answer.

6 0

2 years ago

I’m having a hard time understanding substitution. Please help!

Vikentia [17]

$b_1=\frac{2A}{h}-b_2$

Step-by-step explanation:

Given expression is;

$A=\frac{h(b_1+b_2)}{2}$

Solving for $b_1$

Multiplying both sides by 2

$2*A=\frac{h(b_1+b_2)}{2}*2\\2A=h(b_1+b_2)$

Dividing both sides by h

$\frac{2A}{h}=\frac{h(b_1+b_2)}{h}\\\frac{2A}{h}=b_1+b_2$

Subtracting $b_2$ from both sides

$\frac{2A}{h}-b_2=b_1+b_2-b_2\\\frac{2A}{h}-b_2=b_1\\b_1=\frac{2A}{h}-b_2$

$b_1=\frac{2A}{h}-b_2$

Keywords: division, subtraction

Learn more about subtraction at:

#LearnwithBrainly

3 0

3 years ago

Let g(x) = 2x2 - 11x. Find g(-1).<br> A) -13 Eliminate <br> B) -9 <br> C) 0 <br> D) 13

worty [1.4K]

Solution

g(x) = 2 $x^{2}$ - 11x

Plugging in x = -1 in g(x), we get

g(-1) = 2 $(-1)^{2}$ - 11(-1)

Now we have to simplify it.

g(-1) = 2*1 + 11

g(-1) = 2 + 11

g(-1) = 13

So the answer is D) 13.

Thank you. :)

3 0

3 years ago

Consider the following functions. f1(x) = x, f2(x) = x2, f3(x) = 2x − 4x2 g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, a

bekas [8.4K]

9514 1404 393

Answer:

(c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
NOT linearly independent

Step-by-step explanation:

We want ...

c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0

Substituting for the fn function values, we have ...

c1·x +c2·x² +c3·(2x -4x²) ≡ 0

This resolves to two equations:

x(c1 +2c3) = 0

x²(c2 -4c3) = 0

These have an infinite set of solutions:

c1 = -2c3

c2 = 4c3

Then for any parameter t, including the "trivial" t=0, ...

(c1, c2, c3) = (-2t, 4t, t)

__

f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)

7 0

2 years ago