Answer:
True
Step-by-step explanation:
we know that
The <u><em>Trapezoid Mid-segment Theorem</em></u> states that : A line connecting the midpoints of the two legs of a trapezoid is parallel to the bases, and its length is equal to half the sum of lengths of the bases
see the attached figure to better understand the problem
EF is the mid-segment of trapezoid
EF is parallel to AB and is parallel to CD
EF=(AB+CD)/2
so
The mid-segment of a trapezoid is always parallel to each base
therefore
The statement is true
Answer:
B, C, E, F
Step-by-step explanation:
The following relationships apply.
- the diagonals of a parallelogram bisect each other
- the diagonals of a rectangle are congruent
- the diagonals of a rhombus meet at right angles
- a rectangle is a parallelogram
- a parallelogram with congruent adjacent sides is a rhombus
__
CEDF has diagonals that bisect each other, and it has congruent adjacent sides. It is a parallelogram and a rhombus, but not a rectangle. (B and C are true.)
ABCD has congruent diagonals that bisect each other. It is a parallelogram and a rectangle, but not a rhombus. (There is no indication adjacent sides are congruent, or that the diagonals meet at right angles.) (E and F are true.)
The true statements are B, C, E, F.
Answer:
Step-by-step explanation:
slope-intercept equation for line of slope -5/2 and y-intercept -2:
y = (-5/2)x-2
put into standard form:
(5/2)x + y = -2
5x + 2y = -4
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