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3 years ago

Help with setting up these two problems there 2 different problems

Mathematics

2 answers:

ELEN [110]3 years ago

7 0

I'm not good at math i cant help

schepotkina [342]3 years ago

6 0

Problem 1.

hoppers = 2 * crickets

hoppers + crickets = 561

2*crickets + crickets = 561

problem 2.

adults = 6 * students

adults + students = 490

6 * students + students = 490

that should be enough setup to get you the answers :)

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Find the exact value of sinpi/12

Anastasy [175]

Answer:0.2588

Step-by-step explanation:

To find the exact value for

Sinpi/12

pi=180°

Sin 180/12

Sin15°

=0.2588

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4 years ago

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Deshi has 427 marbles and Elaheh has 394 marbles Deshi wants to give 125 marbles to his little brother how many total marbles wi

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Answer: Deshi will have 302 marbles and Elaheh will have 519.

Step-by-step explanation:

Deshi's Marbles will subtract 125.

427 - 125 = 302.

Elaheh's Marbles will add 125.

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3 years ago

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victus00 [196]

Answer:

Step-by-step explanation:

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3 years ago

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3 years ago

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

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3 years ago