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swat32
3 years ago
8

What are all the expressions that are equivalent to 64?

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

1×64 2×33 4×16 8×8 16×4 33×2 64×1

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What does it mean if your second toe is longer than your first?
motikmotik
Nothing really, it is in my genetics that i have a middle toe longer than my big toe.  My friend doesn't have the genetics and his middle toe is not as long as his big toe.  It is all in genetics.  
5 0
3 years ago
What is the answer to this and show the work please.
Gre4nikov [31]
Which method? There is the substitution method, elimination method, and comparison method
3 0
2 years ago
Find the measures of all four angles if 3·(m∠1+m∠3) = m∠2+m∠4.
mixas84 [53]

Answer:

Step-by-step explanation:

m∠1=m∠3

m∠2=m∠4

3*(m∠1+m∠3)=m∠2+m∠4

3*(m∠1+m∠1)=m∠2+m∠2

3×2 m∠1=2 m∠2

m∠2=3 m∠1

now m∠1+m∠2=180°

m∠1+3 m ∠1=180

4 m∠1=180

m∠1=180/4=45°

m∠3=45°

m∠2=180-m∠1=180-45=135°

m∠4=135°

5 0
3 years ago
Solve for y ; -2y - 2x =4
Deffense [45]
I think this is what you want to do

Your welcome

4 0
2 years ago
Read 2 more answers
A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability
Hoochie [10]

Answer:

The probability  of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

  • A city council consists of seven Democrats and five Republicans.
  • A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

Compute the number of ways to select four people as follows:

{12\choose 4}=\frac{12!}{4!\times (12-4)!}=495

Compute the number of ways to selected two Democrats as follows:

{7\choose 2}=\frac{7!}{2!\times (7-2)!}=21

Compute the number of ways to selected two Republicans as follows:

{5\choose 2}=\frac{5!}{2!\times (5-2)!}=10

Then the probability  of selecting two Democrats and two Republicans as follows:

P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242

Thus, the probability  of selecting two Democrats and two Republicans is 0.4242.

6 0
2 years ago
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