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r-ruslan [8.4K]
3 years ago
11

box contains 12 ​transistors, 3 of which are defective. If 3 are selected at​ random, find the probability of the statements bel

ow.
Mathematics
1 answer:
Mama L [17]3 years ago
6 0

# of ways to select 3 defective:: 3C3 = 1
----
# of random sets of 3:: 12C3 = (12*11*10)/(1*2*3) = 220
----
P(3 defective) = 1/220
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Answer:

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Step-by-step explanation:

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Vera_Pavlovna [14]

Answer:

Option b is the correct answer as both the equations are true for given solution.

Step-by-step explanation:

Given equations are:

-0.1x-0.3y=1.2

0.2x-0.5y=2

We can observe each graph and find the point that is the solution and put the point in the equations to know if that point is the solution

<u>For option A:</u>

(0,4)

Putting x=0 and y = 4 in both equations

-0.1(0)-0.3(4)=1.2\\0-1.2 =1.2\\-1.2 \neq 1.2\\0.2(0)-0.5(4)=2\\0-2 = 2\\-2 \neq 2

This is not the correct answer as both equations are not true with this solution

<u>For Option B:</u>

(0,-4)

Putting x = 0 and y = -4 in both equations

-0.1(0)-0.3(-4)=1.2\\0+1.2 = 1.2\\1.2 = 1.2\\0.2x-0.5y=2\\0.2(0)-0.5(-4) = 2\\2 = 2

Both equations are true for (0,-4) hence it is the solution of the system.

<u>For Option C:</u>

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Not true for both equations

Hence,

Option b is the correct answer.

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Answer:

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Step-by-step explanation:

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4k+mn=n-3
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