a) since a=0 therefore, friction force =0
b) friction = 59.5 × 1 =59.5 N.
c)maximum acceleration = 0.566 × g =5.54 m/s².
<h3>What is Friction force?</h3>
The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction. There are various kinds of friction: Two solid surfaces in touch are opposed to one another's a relative lateral motion by dry friction.
<h3>What is acceleration?</h3>
Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities. The direction of the net force acting on an object determines the direction of its acceleration.
Hence, (a) since a=0 therefore, friction force =0, (b) friction = 59.5 × 1 =59.5 N, (c)maximum acceleration = 0.566 × g =5.54 m/s².
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Answer:
Capacitance = ( 4π×∈×r×R ) / (R-r)
energy store = ( 4π×∈×r×R )×V² / (R-r)
Explanation:
given data
radius = r
radius = R
r < R
to find out
capacitance and how much energy store
solution
we consider here r is inner radius and R is outer radius
so now apply capacitance C formula that is
C = Q/V .................1
here Q is charge and V is voltage
we know capacitance have equal and opposite charge so
V =
here E = Q / 4π∈k²
so
V = Q / 4π∈
V = Q / 4π∈ × ( 1/r - 1/R )
V = Q(R-r) / ( 4π×∈×r×R )
so from equation 1
C = Q/V
Capacitance = ( 4π×∈×r×R ) / (R-r)
and
energy store is 1/2×C×V²
energy store = ( 4π×∈×r×R )×V² / (R-r)
Answer :
The time is
(B) is correct option.
Explanation :
Given that,
Diameter = 100000 light year
Velocity = 0.99 c
We need to calculate the time
Using formula of time
Put the value into the formula
Hence, The time is
Answer:
The Force between the two charges is an attractive force of 16,000N
Explanation:
Expression for the electric force between the two charges is given by
F = (k*q1*q2) / r^2
Here, k = constant = 9 x 10^9 N*m^2 / C^2
q1 = - 2.0x10^-4C
q2 = + 8.0x10^-4C
r = 0.30 m
Substitute the given values in the above expression -
One charge is + and the other is a -, therefore the net force is an attractive force (opposites atract)
The attraction force is:
F= 9.0x10^9 * 2.0x10^-4 *8.0x10^-4 N/ 0.30^2
F= 16,000N
Answer:
45.5 m
Explanation:
m = 2 kg, h = 20 m, E = 500 J, radius of earth = R, mass of earth = M
find the new height H
at h, the potential energy = -GMm/(R + h)
at H, the potential energy = -GMm/(R + H)
increase of the potential energy
= [-GMm/(R + H)] - [-GMm(R + h)]
= GMm[1/(R + h) - 1/(R + H)] = E
1/(R + h) - 1/(R + H) = E/(GMm)
(H - h)/[(R + H)(R + h)] = E/(GMm)
R + h ≈ R, R + H ≈ R
so (H - h)/R² = E/(GMm)
H - h = ER²/(GMm)
note GM/R² = g = 9.81 m/s²
so H - h = E/(mg)
H = h + E/(mg) = 20 + 500/(2*9.81) = 45.5 m