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vodomira [7]
3 years ago
6

If Earth were the size of a grape, how big would the Moon be? How far away would the Moon be from the Earth? How large would the

Sun be? How far away would it be from grape-sized Earth?​
Physics
1 answer:
dangina [55]3 years ago
3 0

Answer:

The moon would be the size of a raspberry. It would be as far a like 4 or 5 inches. The sun would be as big as an cantaloupe.The sun would be as far as 10 or 11 inches.

Explanation:

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Assume that an intercontinental ballistic missile goes from rest to a suborbital speed of 6.50 km/s in 60.0 s (the actual speed
olasank [31]

Answer:

Average acceleration is (11.05)g\ m/s^2

Explanation:

It is given that,

Initial velocity, u = 0

Final velocity, v = 6.5 km/s = 6500 m/s

Time taken, t = 60 s

Acceleration, a=\dfrac{v-u}{t}

a=\dfrac{v}{t}  

a=\dfrac{6500\ m/s}{60}  

a=108.33\ m/s^2

Since, g=9.8\ m/s^2

So, a=(11.05)g\ m/s^2

So, the angular acceleration of the missile is (11.05)g\ m/s^2. Hence, this is the required solution.

4 0
3 years ago
An aurora occurs when ____
ASHA 777 [7]

The short answer to how the aurora happens is that energetic electrically charged particles (mostly electrons) accelerate along the magnetic field lines into the upper atmosphere, where they collide with gas atoms, causing the atoms to give off light.

7 0
3 years ago
How can we produce energy by turning a turbine?​
maw [93]
Wind turbines work on a simple principle: instead of using electricity to make wind—like a fan—wind turbines use wind to make electricity. Wind turns the propeller-like blades of a turbine around a rotor, which spins a generator, which creates electricity.
7 0
3 years ago
What charges form a neutral charge?
brilliants [131]

A negative to a negative charge will make a neutral charge.

4 0
3 years ago
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An astronaut is standing on the surface of a planetary satellite that has a radius of 1.74 × 10^6 m and a mass of 7.35 × 10^22 k
ExtremeBDS [4]

Answer:

2.87 km/s

Explanation:

radius of planet, R = 1.74 x 10^6 m

Mass of planet, M = 7.35 x 10^22 kg

height, h = 2.55 x 10^6 m

G = 6.67 x 106-11 Nm^2/kg^2

Use teh formula for acceleration due to gravity

g=\frac{GM}{R^{2}}

g=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{1.74^{2}\times 10^{12}}

g = 1.62 m/s^2

initial velocity, u = ?, h = 2.55 x 10^6 m , final velocity, v = 0

Use third equation of motion

v^{2}=u^{2}-2gh

0 = v² - 2 x 1.62 x 2.55 x 10^6

v² = 8262000

v = 2874.37 m/s

v = 2.87 km/s

Thus, the initial speed should be 2.87 km/s.

6 0
3 years ago
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