Question

1.) A negative charge of -2.0x10-4 C and a positive charge of 8.0x10-4 C are

Answer 1

Answer:

The Force between the two charges is an attractive force of 16,000N

Explanation:

Expression for the electric force between the two charges is given by

F = (k*q1*q2) / r^2

Here, k = constant = 9 x 10^9 N*m^2 / C^2

q1 = - 2.0x10^-4C

q2 = + 8.0x10^-4C

r = 0.30 m

Substitute the given values in the above expression -

One charge  is + and the other is a -, therefore the net force is an attractive force (opposites atract)

The attraction force is:

F= 9.0x10^9 * 2.0x10^-4 *8.0x10^-4 N/ 0.30^2

F= 16,000N