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2 years ago

1.) A negative charge of -2.0x10-4 C and a positive charge of 8.0x10-4 C are

Physics

1 answer:

exis [7]2 years ago

6 0

Answer:

The Force between the two charges is an attractive force of 16,000N

Explanation:

Expression for the electric force between the two charges is given by

F = (k*q1*q2) / r^2

Here, k = constant = 9 x 10^9 N*m^2 / C^2

q1 = - 2.0x10^-4C

q2 = + 8.0x10^-4C

r = 0.30 m

Substitute the given values in the above expression -

One charge is + and the other is a -, therefore the net force is an attractive force (opposites atract)

The attraction force is:

F= 9.0x10^9 * 2.0x10^-4 *8.0x10^-4 N/ 0.30^2

F= 16,000N

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Two round concentric metal wires lie on a tabletop, one inside the other. The inner wire has a diameter of 18.0 cm and carries a

Helen [10]

Answer:

Explanation:

The wires are in circular shape . They have common center .

magnetic field due to circular wire is given by the formula

B = $\frac{\mu_0\times I }{2r}$

where I is current , r is radius of the coil .

magnetic field due to inner wire

= $\frac{\mu_0\times 10 }{2\times.09}$

magnetic field due to outer wire

= $\frac{\mu_0\times I }{2\times.15}$

These should be equal and opposite so that by cancelling each other , they create zero field.

$\frac{\mu_0\times 10 }{2\times.09}$ = $\frac{\mu_0\times I }{2\times.15}$

I = 16.66 A

Direction of current should be in opposite direction ie anticlockwise when looking from above.

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3 years ago

The actual depth of a shallow pool 1.00 m deep is not the same as the apparent depth seen when you look straight down at the poo

DedPeter [7]

Answer:

d' = 75.1 cm

Explanation:

It is given that,

The actual depth of a shallow pool is, d = 1 m

We need to find the apparent depth of the water in the pool. Let it is equal to d'.

We know that the refractive index is also defined as the ratio of real depth to the apparent depth. Let the refractive index of water is 1.33. So,

$n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{1\ m}{1.33}\\\\d'=0.751\ m$

d' = 75.1 cm

So, the apparent depth is 75.1 cm.

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3 years ago

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sergeinik [125]

Answer:

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3 years ago

A block is pulled across a flat surface at a constant speed using a force of 50 newtons at an angle of 60 degrees above the hori

vladimir2022 [97]

The magnitude of the friction force is 25 N

Explanation:

To solve this problem, we just have to analyze the forces acting on the block along the horizontal direction. We have:

The horizontal component of the pulling force, $F cos \theta$ , where F = 50 N is the magnitude and $\theta=60^{\circ}$ is the angle between the direction of the force and the horizontal; this force acts in the forward direction
The force of friction, $F_f$ , acting in the backward direction

According to Newton's second law, the net force acting on the block in the horizontal direction must be equal to the product between the mass of the block and its acceleration:

$\sum F_x = ma_x$

where

m is the mass of the block

$a_x$ is the horizontal acceleration

However, the block is moving at constant speed, so the acceleration is zero:

$a_x = 0$

So the equation becomes

$\sum F_x = 0$ (1)

The net force here is given by

$\sum F_x = F cos \theta - F_f$ (2)

And so, by combining (1) and (2), we find the magnitude of the friction force:

$F cos \theta - F_f = 0\\F_f = F cos \theta = (50)(cos 60^{\circ})=25 N$

Learn more about force of friction:

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3 years ago

You drive your car 3 hrs at an average of 130 km how far did you go

Bingel [31]

You have traveled 390 km. In order to find your answer all you have to do is multiply your speed which is 130 km/h by 3 hrs. That's my friend is how you get your answer! Have a great day!

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3 years ago