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3 years ago

8

A little girl got a new puppy and wants to keep track of its growth. Every week she measures the puppy's length from head to tai

l in inches. What would represent the output of the relation?
- The size of the puppy's head
-The length of the puppy from head to tail
-The amount of time she has the puppy
-How fast the puppy grows

1 answer:

Grace [21]3 years ago

4 0

Answer:

Well I would say it is D.

Step-by-step explanation:

I say D because if she is measuring it every week then she is wanting to know how fast the puppy grows.

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Find an m > 0 such that the the equation x^4−(3m+2)x^2+m^2=0 has four real solutions that form an arithmetic sequence.

Aleonysh [2.5K]

Answer:

The value of m is 6.

Step-by-step explanation:

Here, the given equation,

$x^4-(3m+2)x^2+m^2=0$

$x^4+0x^3-(3m+2)x^2+0x+m^2=0$

Let the roots of the equation are a-3b, a-b, a+b and a + 3b, ( they must be form an AP )

Thus, we can write,

$a-3b+a-b+a+b+a+3b=\frac{\text{coefficient of }x^3}{\text{coefficient of }x^4}$

$=\frac{0}{1}=0$

$\implies a=0----(1)$

$(-3b)(-b)+(-b)(b)+(b)(3b)+(3b)(-3b)+(-b)(3b)+(-3b)(b)=\frac{\text{coefficient of }x^2}{\text{coefficient of }x^4}}$

$=\frac{-3m-2}{1}$

$3b^2-b^2+3b^2-9b^2-3b^2-3b^2=-3m-2$

$-10b^2=-3m-2$

$\implies b^2=\frac{3m+2}{10}-----(2)$

$(-3b)(-b)(b)(3b)=\frac{\text{Constant term}}{\text{coefficient of}x^4}= m^2$

$9b^4=m^2$

$9(\frac{3m+2}{10})^2=m^2$

$9(\frac{9m^2+4+12m}{100})=m^2$

$81m^2+36+108m=100m^2$

$-19m^2+108m+36=0$

$19m^2-108m-36=0$

$19m^2-114m+6m-36=0$

$19m(m-6)+6(m-6)=0$

$(19m+6)(m-6)=0$

$\implies m=-\frac{6}{19}\text{ or }m=6$

But m > 0,

Hence, the value of m is 6.

4 0

3 years ago

I just need anyone to tell me if it's correct:<br><br> Is 8: True<br> and<br> Is 9: False<br> ?

natta225 [31]

I’m pretty sure

8. would be false because BK would be 12 where as DF is 10.8

9. is true

4 0

3 years ago

Read 2 more answers

The data set of the diameters of the metal cylinders manufactured an automatic machine has sample size of n=29, mean of x= 49.98

Lena [83]

Answer:

we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )

Step-by-step explanation:

Given data

n=29

mean of x = 49.98 mm

S = 0.14 mm

μ = 50.00 mm

Cl = 95%

to find out

Can we be 95% confident that machine calibrated properly

solution

we know from t table

t at 95% and n -1 = 29-1 = 28 is 2.048

so now

Now for 95% CI for mean is

(x - 2.048 × S/√n , x + 2.048 × S/√n )

(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )

( 49.926757 , 50.033243 )

hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )

8 0

3 years ago

Find the measure of the arc indicated.

ella [17]

A.) 155
123 + 47 + 35 = 205
Subtract 205 with 360 (360 is the measure of a circle) and you will be left with 155°.

7 0

2 years ago

On a coordinate plane, the orange K is shifted to form the purple K, reflected across the x-axis to form the green k, and rotate

PIT_PIT [208]

Answer:

the green kin quadrant IV

Step-by-step explanation:

i took the quiz and got it right

3 0

2 years ago