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diamong [38]
3 years ago
10

Help me with all ten and i will mark u brainlist owo

Mathematics
1 answer:
Gnoma [55]3 years ago
3 0

Answer:

Chile all 10 QuEsTiOns. My brain died.

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Choose the numbers to create a story problem that represent 4 divide 1/3
likoan [24]

Answer:

Jack wants to give a treat to his 4 friends. Jack buys a big chocolate

filled cake. He divides the cake into 1/3 pieces. How much cake did each friend get?

7 0
3 years ago
Is y=2x+3 a proportional relationship?​
Liono4ka [1.6K]

Answer:

no

Step-by-step explanation:

2x plus 3 is not proportional to y on a graph

5 0
3 years ago
A semicircle with diameter PQ sits on an isosceles triangle PQR to form a region shaped like a two-dimensional ice- cream cone,
Ksivusya [100]

The limit of a(x)/b(x) as x approaches 0 is gotten as;

lim a(x)/b(x); x→0 = 0

  • The image showing the semi circle and isosceles triangle is missing and so i have attached it.

  • Formula for <em>area</em> of a semi circle is;

a(x) = A = ¹/₂πr²

  • <em>Area</em> of triangle is;

b(x) = A =  ¹/₂ × base × height

  • From the image, ∠PQR = θ

Thus; a(x) = ¹/₂π(10 sin (θ/2))²

a(x) =  ¹/₂π(100 sin² (θ/2))

Similarly;

b(x) =  ¹/₂(20 sin (θ/2)) × (10 cos (θ/2))

b(x) = 100 sin (θ/2) cos (θ/2)

  • Thus;

a(x)/b(x) = ¹/₂π(100 sin² (θ/2)) ÷ 100 sin (θ/2) cos (θ/2)

100 will cancel out and the sin (θ/2) at the denominator will be eradicated

upon further simplification to give;

a(x)/b(x) = ¹/₂π(sin (θ/2)) ÷ cos (θ/2)

In trigonometry, we know that; tan θ = sin θ/cos θ

Thus;

a(x)/b(x) = ¹/₂π(sin (θ/2)) ÷ cos (θ/2) =  ¹/₂π(tan (θ/2))

We want to find the limit as θ approaches <em>zero.</em>

Thus;

lim θ → 0 =  ¹/₂π(tan (0/2))

⇒ ¹/₂π tan 0

⇒ 0

Read more at; https://brainly.in/question/9387458

3 0
2 years ago
Which angles are adjacent to
zlopas [31]
Angle DEA is the correct answer

Hope my answer helps!
3 0
3 years ago
SOMEBODY ANYBODY HELP ME PLZ ONLY 1 QUESTION
natima [27]

Answer:

the 4th one

Step-by-step explanation:

as 2x + 4 cubed is 8x cubed + 64

6 0
3 years ago
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