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aleksandr82 [10.1K]
3 years ago
14

A phone company charges $0.45 for the first minute and $0.35 for each additional minute for a long distance call. Which numerica

l expression can be used to find the cost of a 20-minute phone call?
Mathematics
2 answers:
Vinvika [58]3 years ago
8 0

0.45+19(0.35)

Total cost $7.10 (0.45+6.65)

AnnZ [28]3 years ago
8 0

Answer:

Total cost for 20 minutes = $0.45  + $0.35 * 19.

Step-by-step explanation:

Given  : A phone company charges $0.45 for the first minute and $0.35 for each additional minute for a long distance call.

To find : Which numerical expression can be used to find the cost of a 20-minute phone call.

Solution : We have given

Company charge for 1 minute = $0.45 .

For other minutes = $0.35 .

Total minutes he called = 20 minutes

Cost of 1 minute call = $0.45 .

Cost of 19 minutes call = $0.35 * 19.

Total Cost for 20 minute = Cost of 1 minute + Cost pf 19 minutes.

Total cost for 20 minutes = $0.45  + $0.35 * 19.

Therefore, Total cost for 20 minutes = $0.45  + $0.35 * 19.

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Show your work F(x)=5x^2-4x+1 G(x)=3x-2 H(x)=x+1 K(x)= 4x What is (g*h)(x)= What is g(k(x))= What is k(g(0)) =
andre [41]

<u>Answer</u><u>:</u>

— What is (g × h)(x)?

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>3x²</em><em>+</em><em>x-2</em>

— What is g(k(x))?

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>12x</em><em> </em><em>-</em><em> </em><em>2</em><em> </em><em>or</em><em> </em><em>2</em><em>(</em><em>6x-1</em><em>)</em>

<em>—</em><em> </em>What is k(g(0))

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>-</em><em /><em>8</em>

<u>Explanation:</u>

Given these functions —

f(x)  = 5 {x}^{2}  - 4x + 1 \\ g(x) = 3x - 2 \\ h(x) = x + 1 \\ k(x) = 4x

<u>Find</u><u> </u><u>(</u><u>g</u><u> </u><u>×</u><u> </u><u>h</u><u>)</u><u>(</u><u>x</u><u>)</u><u />

(g \times h)(x) = g(x) \times h(x)

Substitute g(x) = 3x - 2 and h(x) = x + 1

(3x - 2) \times (x + 1) \\ (3x - 2)(x + 1)

Multiply the polynomial.

3 {x}^{2}  + 3x - 2x - 2

Subtract - 2x out of 3x —

3 {x}^{2}  + x - 2

Thus, the answer is —

(g \times h)(x) = 3 {x}^{2}  + x - 2

<u>Find</u><u> </u><u>(</u><u>g</u><u>(</u><u>k</u><u>(</u><u>x</u><u>)</u><u>)</u><u />

Substitute k(x) = 4x in g(x).

g(x) = 3x - 2 \\ k(x) = 4x

g(k(x)) = g(4x)

g(4x) = 3(4x) - 2

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g(4x) = 12x - 2

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g(k(x)) = 12x - 2

<u>Alternative</u><u> </u><u>Solution</u>

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From k(x) and g(0) —

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Substitute g(0) = -2 in k(x)

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