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olga55 [171]
2 years ago
12

I need help please ASAP !

Mathematics
2 answers:
pav-90 [236]2 years ago
6 0

Answer:

lll only

Step-by-step explanation:

I did a quiz similar to that I hope you make a good grade!

Natasha2012 [34]2 years ago
3 0

Answer:

III only

Step-by-step explanation:

lkjhgfdsaasdfghjkjhgf

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Simplify the expression (2y+1)-4y^2+2
Katena32 [7]

Answer:

-4y^2+2y+3

Step-by-step explanation:

(2y+1)-4y^2+2

2y+1-4y^2+2

-4y^2+2y+1+2

-4y^2+2y+3

5 0
2 years ago
Read 2 more answers
A reading teacher recorded the number of pages read in an hour by each of her
Ymorist [56]

Answer:

the lower quartile should be 43.5, not 44, therefore the 3 is the wrong statistic

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie
allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x  = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan 53^\circ=\frac{150-x}{h}

\displaystyle \tan 48^\circ=\frac{x}{h}

From the last equation:

x=h.\tan 48^\circ

Substituting into the first equation:

\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}

Operating on the right side:

\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ

Rearranging:

\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}

Solving for h:

\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}

Calculating:

h = 61.5 m

The building is 61.5 m tall

5 0
3 years ago
6-√8 divide √2-1
agasfer [191]

Answer:

4\sqrt{2}  +2

Step-by-step explanation:

\frac{6-\sqrt{8}}{\sqrt{2}-1}

=\frac{6-\sqrt{8}}{\sqrt{2}-1} ×\frac{\sqrt{2}+1}{\sqrt{2}+1}

=\frac{(6-\sqrt{8})(\sqrt{2}+1)}{2-1}

=6\sqrt{2} + 6 -\sqrt{8}\sqrt{2} - \sqrt{8}

=6\sqrt{2} + 6 - 4 - \sqrt{8}

=6\sqrt{2} + 2 - \sqrt{8}

=6\sqrt{2} + 2 - 2

=4\sqrt{2}  +2

for \sqrt{8} = 2\sqrt{2} ,

\sqrt{8} = \sqrt{2*2*2}

     = (\sqrt{2})^2 × \sqrt{2}

     =2 ×\sqrt{2}

5 0
3 years ago
What is area?? <br> Here is the question I’m trying to answer <br><br> Part B
zheka24 [161]
I assume you are calculating the total area to be painted.
Then 3 x 8.3 x 7.5 = 186.75 sq. ft.
6 0
3 years ago
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