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Mazyrski [523]
4 years ago
15

Given the points P (-1, -3) and R (2, -3), find the slope.

Mathematics
1 answer:
lara31 [8.8K]4 years ago
4 0

Answer:

0, the y stays the same.

Step-by-step explanation:

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What is the simplified form of 20 times x to the sixth power over 15 times y to the fifth power times the fraction 5 times y squ
Delvig [45]
In order to easily picture out the operation involving fractions, let's write it in an algebraic equation. So, the above description is written as

20x⁶/15y⁵ × 5y²/6x⁴

The first thing to do is to simplify the easiest terms: the constants. Just multiply all the constants on the numerator and all the constants on the denominator independently. The simplified constant becomes

(20*5)/(15*6) = 10/9

So, the equation to be solved now is 

10x⁶y²/9y⁵ x⁴

So, I also multiplied all the variables in the numerator and denominator independently, just like the constants. Then, you apply the laws of exponents. When you divide terms with exponents of the same value of the base, you subtract the exponent on the numerator minus the denominator. It goes like this:

10/9 * x⁶⁻⁴*y²⁻⁵ = 10/9*x²y⁻³

Now, when the exponent as written to the power of a negative exponent, just simply take its reciprocal to make it positive. So, the final answer is

10x²/9y³ or that is letter D.
8 0
4 years ago
Mr. Walker gave his class the function f(x) = (x + 3)(x + 5). Four students made a claim about the function. Each student’s clai
Scrat [10]

the only student that is correct is Stepheh. "The vertex is at (–4, –1)."

<h3>Which claims are true?</h3>

Here we have the quadratic equation:

f(x) = (x + 3)*(x + 5)

The first claim is: "The y-intercept is at (15, 0)."

This is clearly false, as the y-intercept is at x = 0, and in that point we have x = 15.

The second claim is:

"The x-intercepts are at (–3, 0) and (5, 0)"

This is false, in the factored equation we can see that the x-intercepts are x =-3 and x = -5.

Third claim:

"The vertex is at (-4, -1)"

The middle value between the zeros is:

(-3 + (-5))/2 = -4

Evaluating the function in x = -4 we get the y-value of the vertex:

f(-4) = (-4 + 3)*(-4 + 5) = -1*1 = -1

So the vertex is at (-4, -1), this claim is true.

The fourth claim is:

"The midpoint between the x-intercepts is at (4, 0)."

Which is false, we already saw that the midpoint between the x-intercepts is at x = -4

Then the only student that is correct is Stepheh. "The vertex is at (–4, –1)."

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

3 0
2 years ago
A regular pentagon has side lengths of 14.1 centimeters and an apothem with length 12 centimeters. What is the approximate area
Katena32 [7]

Answer:

423 cm^2

Step-by-step explanation:

Area of a regular pentagon = Pa/2, where P = the perimeter and a = the apothem.

We can find the perimeter by

P = 5s where s is the side length since the pentagon is regular

P = 5( 14.1)

P = 70.5

A = P*a/2

   = 70.5 ( 12)/2

  =423 cm^2

7 0
3 years ago
Read 2 more answers
which of the following situations can be modeled with a linear function A. The area y, of a square with side x b. The area, y, o
Ulleksa [173]

Answer:

Option D. The circumference

Step-by-step explanation:

A). Area 'y' of square with side 'x' will be represented by

    y = (Side)²

    y = x²

Since the degree of this polynomial function is 2, It's a quadratic equation.

B). Area of the circle = πr²

    y = π(x)²

Since the degree of this polynomial function is 2, It's a quadratic equation.

C). Volume of a cube = (Side)³

    y = x³

Since the degree of this polynomial function is 3, It's not a linear function.

D). Circumference of the circle = 2πr

    y = 2π(x)

Since the degree of this polynomial function is 1, it's a linear function.

4 0
3 years ago
4/3 , 16/12 equal or no
maw [93]
Yes 16/12 divided by 4 by the numerator and denominator is 4/3
5 0
4 years ago
Read 2 more answers
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