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dimulka [17.4K]
3 years ago
13

Use the following situation for the next few questions:

Mathematics
1 answer:
Olegator [25]3 years ago
4 0

Answer:

5 oil changes.

Step-by-step explanation:

60 = 12x + 15y

60 = 12x + 15(0)

60 = 12x + 0

60

---- = x

12

5 = x

You might be interested in
A 4-cup bottle of vegetable oil costs 2.80. What is the price per pint
german

Answer:

$1.40 per pint

Step-by-step explanation:

4 cups is the same as 2 pints.

If 2 pints cost $2.80

divide $2.80 by 2

and get $1.40 per pint

8 0
3 years ago
A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are
IRINA_888 [86]

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5 percent of these are defective.

This means that p = 0.05

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025

0.0025 = 0.25% probability that both are defective

4 0
3 years ago
A ball is thrown from an initial height of 4 feet with an initial upward velocity of 17ft/s. The ball's height h (in feet) after
iVinArrow [24]
Use quadratic formula 
8= 4 +17t -16t^2
16t^2 - 17 t + 4
answers (17 + square root (33)) /32 and  (17 - square root (33)) /32
4 0
4 years ago
Find y when x=15 if y=6 when x=30
Elan Coil [88]

Answer:


Step-by-step explanation:

the answer would be nine

6 0
3 years ago
Easy math, but not sure what I did wrong.
Ierofanga [76]

Answer:

8

Step-by-step explanation:

In his 5th year, he took 3 times as many exams as the first year.  So the number of exams taken in the 5th year must be a multiple of 3.

If a₁ = 1, then a₅ = 3.  However, this isn't possible because we need 4 integers between them, and a sum of 31.

If a₁ = 2, then a₅ = 6.  Same problem as before.

If a₁ = 3, then a₅ = 9.  This is a possible solution.

If a₁ = 4, then a₅ = 12.  If we assume a₂ = 5, a₃ = 6, and a₄ = 7, then the sum is 34, so this is not a possible solution.

Therefore, Alex took 3 exams in his first year and 9 exams in his fifth year.  So he took 19 exams total in his second, third, and fourth years.

3 < a₂ < a₃ < a₄ < 9

If a₂ = 4, then a₃ = 7 and a₄ = 8.

If a₂ = 5, then a₃ = 6 and a₄ = 8.

If a₂ = 6, then there's no solution.

So Alex must have taken 8 exams in his fourth year.

4 0
3 years ago
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