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Lilit [14]
3 years ago
8

In a survey of 12 people, it was found that an average of $36 was spent on their child's last birthday gift with a standard devi

ation of $11. Estimate the mean amount people spend on their child's last birthday gift with 80% confidence using the appropriate critical value to three decimal places. Enter your answer as equations or as numbers rounded to four decimal places.
Mathematics
1 answer:
Nataliya [291]3 years ago
3 0

Answer:

(27.3692 ; 44.6308)

Step-by-step explanation:

Mean, xbar = 36

Standard deviation, s = 11

Sample size, n = 12

Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718

Confidence interval :

Xbar ± Margin of error

Margin of Error = Tcritical * s/sqrt(n)

Margin of Error = 2.718 * 11/sqrt(12) = 8.6308

Confidence interval :

Lower boundary : 36 - 8.6308 = 27.3692

Upper boundary : 36 + 8.6308 = 44.6308

(27.3692 ; 44.6308)

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Suppose you can factor x^2 +bx +c as (x+p)(x+q) . If c&lt;0, what could be the possible values of p and q?
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Let's solve it smartly!
Given expression: x^{2} + bx +c --- (A)
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By comparing (B) with (A), we can say that:
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Now, as the condition says, c<0, it means either p or q is negative. Both cannot be positive or both cannot be negative.

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