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3 years ago

Please help meeeeeeeeee

Mathematics

2 answers:

Ilya [14]3 years ago

7 0

Midpoint formula ((x1+x2)/2, (y1+y2)/2)
((4+10)/2, (2+4)/2)

answer is (7,3)

irina1246 [14]3 years ago

7 0

Answer:

(7,3)

Step-by-step explanation:

You're welcome.

You might be interested in

Which ordered pair is identified by the letter "G" on this coordinate grid?

Natasha2012 [34]

Hey there!

When we say coordinate pair, we usually express our pair in the form of:

(x, y)

This means the point on the x axis is first, and the point on the y is second in the parenthetical format of coordinates. We know that the x coordinate is the horizontal one, while the y is vertical.

If we start with the x axis, we see that our point, G, is just below the number 2. That means our x coordinate is 2. For the y coordinate, we see that the point is directly lined up with the -3, therefore our y coordinate is -3.

Therefore, our coordinates are (2, -3).

Hope this helps!

8 0

3 years ago

Please help!

SSSSS [86.1K]

A the correct answer pa brainless po

5 0

2 years ago

Read 2 more answers

Opel runs a bakery, and it takes her 15 minutes to make a batch of cookie dough. What is Opel's rate per minute for making batch

8090 [49]

Answer:

ok so it can either be 0.07x or 1/15x (they are equal)

(both being 1/15th of a cookie per minute)

3 0

4 years ago

A doctor is interested in people who have experienced an unexplained episode of vitamin D intoxication. She took a SRS of size 1

Mila [183]

Answer:

(a) (2.573, 3.167) is the 99% confidence interval for $\mu$ the true mean calcium level of the population of people who experienced an unexplained episode of vitamin D intoxication.

(b) There is a 99% probability that the average calcium level of all people who have experienced an unexplained episode of vitamin D intoxication is in the interval.

Step-by-step explanation:

If we have a random sample of size n from a normal distribution with mean $\mu$ and standard deviation $\sigma$ , then we know that $\bar{X}$ is normally distributed with mean $\mu$ and standard deviation $\sigma/n$ . Therefore we can use $(\bar{X}-\mu)/\frac{\sigma}{\sqrt{n}}$ as a pivotal quantity.

We have a sample size of n = 12. The sample mean is $\bar{x}$ = 2.87 mmol/l and the standard deviation is $\sigma = 0.40$ . The confidence interval is given by $\bar{x}\pm z_{\alpha/2}(\frac{\sigma}{\sqrt{n}})$ where $z_{\alpha/2}$ is the $\alpha/2$ th quantile of the standard normal distribution. As we want the 99% confidence interval, we have that $\alpha = 0.01$ and the confidence interval is $2.87\pm z_{0.005}(\frac{0.40}{\sqrt{12}})$ where $z_{0.005}$ is the 0.5th quantile of the standard normal distribution, i.e., $z_{0.005} = -2.5758$ . Then, we have $2.87\pm (-2.5758)(\frac{0.40}{\sqrt{12}})$ and the 99% confidence interval is given by (2.573, 3.167)

(b) We found a 99% confidence interval for the true mean calcium level of the population of people who experienced an unexplained episode of vitamin D intoxication. Therefore, there is a 99% probability that the average calcium level of all people who have experienced an unexplained episode of vitamin D intoxication is in the interval.

8 0

4 years ago

An arrow is launched upward with a velocity of

anyanavicka [17]

Answer:

Step-by-step explanation:

The velocity of the arrow when it was launched upwards is 320 feet per second. The height of the platform from which it was launched is 50 ft

This means that the arrow is already 50 feets from the ground before moving upwards.

The height that it attains on moving from 50 feets will be determined by Newton's formula of motion.

v^2 = u^2 + 2as

u = initial velocity = 320 feet per second.

1 feet per second = 0.305 meters per second

320 feet per second = 320× 0.305

= 97.6 feets per second

a = acceleration due to gravity =

- 32.17405 feet/second^2 because the arrow is moving upwards)

s =maximum height of the arrow

v = final velocity = 0 feet/second

Substituting into the equation,

0^2 = 97.6^2 + 2×- 32.17405 × s

0 = 9525.76 - 64.3481s

64.3481s = 9525.76

s = 9525.76/64.3481 = 148.03 feets

Total height from the ground would be

148.03 + 50 = 198.03 feets

5 0

3 years ago