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Svetllana [295]
3 years ago
5

Please help meeeeeeeeee

Mathematics
2 answers:
Ilya [14]3 years ago
7 0
Midpoint formula ((x1+x2)/2, (y1+y2)/2)
((4+10)/2, (2+4)/2)

answer is (7,3)
irina1246 [14]3 years ago
7 0

Answer:

(7,3)

Step-by-step explanation:

You're welcome.

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10+-4=6
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Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).
storchak [24]

Answer:

P=16.53\ units

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(2-2)^{2}}

d=\sqrt{(-1)^{2}+(0)^{2}}

d=\sqrt{1}

dPQ=1\ unit

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

dQR=\sqrt{41}\ units

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

d=\sqrt{(3+2)^{2}+(-2+2)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

dRS=5\ units

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-1)^{2}+(-4)^{2}}

dPS=\sqrt{17}\ units

step 5

Find the perimeter

P=PQ+QR+RS+PS

substitute the values

P=1+\sqrt{41}+5+\sqrt{17}

P=6+\sqrt{41}+\sqrt{17}

P=16.53\ units

5 0
3 years ago
A rectangle measures 8/3 inches by 9/4 inches. What is its area?
GREYUIT [131]

Answer:

To find the area, you have to multiply the length times the width

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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