Fundamental Theorem of Algebra...

Mathematics

1 answer:

Fittoniya [83]3 years ago

4 0

Answer:

A real root of fifth-grade multiplicity/No complex roots.

Step-by-step explanation:

The Fundamental Theorem of Algebra states that every polynomial with real coefficients and a grade greater than zero has at least a real root. Let be $f(x) = (x+7)^{5}$ , if such expression is equalized to zero and handled algebraically:

1) $(x+7)^{5} = 0$ Given.

2) $(x+7)\cdot (x+7)\cdot (x+7)\cdot (x+7)\cdot (x+7) = 0$ Definition of power.

3) $x+7=0$ Given.

4) $x = -7$ Compatibility with the addition/Existence of the additive inverse/Modulative property/Result.

This expression has a real root of fifth-grade multiplicity. No complex roots.

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Answer:

A=BQ

Step-by-step explanation:

In order to find an expression, you can use the definition of the dividend in a division:

$A=BC + R$

where A is the dividend, B is the divisor, Q is the quotient (the result of the division) and R is the remainder of the division.

Let A represent the integer variable number of prizes and B represent the integer variable number of participants.

In this case R=0 and B≠0, therefore:

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