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2 years ago

Find the length of the missing side of the triangle to the nearest tenth.

Mathematics

1 answer:

babymother [125]2 years ago

7 0

Hey! So you’re gonna need to use the Pythagorean Theorem (a^2 + b^2 = c^2).
You’re looking for one of the legs here, so after inputting the values your equations should look like this: 6^2 + b^2 = 10^2.
Next, find what the numbers squared are: 36 + b^2 = 100.
Then, isolate the variable: b^2 = 64.
Lastly, square root both sides: √b^2 = √64.
You should find the answer is 8.

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In triangle Uvw , the measure of angle w=90°, the measure of angle u=50 , and wu = 27 feet. Find

sergij07 [2.7K]

Answer:

32.2 feet

using trigonometry, we find that sin(u)=VW/WU

sin50=VW/27

27sin50=32.177347

VW=32.2

5 0

2 years ago

What is the vertex of the function y=|x+3| - 2?

mylen [45]

Answer:

3. (-3,-2)

Step-by-step explanation:

For an absolute value the equation, the transformations are as shown:

y= ±a|b(x-h)|+k.

'h' and 'k' are the vertex coordinates, meaning if y= |x+3|-2:

h= -3

and k= -2

Therefore, we get:

(-3,-2)

4 0

2 years ago

Read 2 more answers

How do you know if a net will fold into a pyramid?

Natalka [10]

Step-by-step explanation:

A pyramid is made when 4 triangle meet on square then mate on each together .

4 0

1 year ago

40 degree, 3x, and 4x solve for x

Alex73 [517]

Answer:

The value of x would be 20

Step-by-step explanation:

To solve this triangle, we need to first note that all triangles have 180 degrees. So we can add these all together and set equal to 180.

40 + 3x + 4x = 180

40 + 7x = 180

7x = 140

x = 20

8 0

3 years ago

Paul and jose are trying to measure the height of a tree. paul is standing 19m from the foot of the tree and measures the angle

Nina [5.8K]

The firts thig we are going to do is create tow triangles using the angles of elevation of Paul and Jose. Since the problem is not giving us their height we'll assume that the horizontal line of sight of both of them coincide with the base of the tree.
We know that Paul is 19m from the base of the tree and its elevation angle to the top of the tree is 59°. We also know that the elevation angle of Jose and the top of the tree is 43°, but we don't know the distance between Paul of Jose, so lets label that distance as $x$ .
Now we can build a right triangle between Paul and the tree and another one between Jose and the tree as shown in the figure. Lets use cosine to find h in Paul's trianlge:
$cos(59)= \frac{19}{h}$
$h= \frac{19}{cos(59)}$
$h=36.9$
Now we can use the law of sines to find the distance $x$ between Paul and Jose:
$\frac{sin(43)}{36.9} = \frac{sin(16)}{x}$
$x= \frac{36.9sin(16)}{sin(43)}$
$x=14.9$

Now that we know the distance between Paul and Jose, the only thing left is add that distance to the distance from Paul and the base of the tree:
$19m+14.9=33.9m$

We can conclude that Jose is 33.9m from the base of the tree.

3 0

3 years ago