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ss7ja [257]
3 years ago
6

Blanche bought a 5-year cd for $7100 with an apr of 2.8%, compounded quarterly, but she wants to take all her money out 9 months

early. the early redemption fee for the cd is 3 months' interest on the original principal. help blanche determine how much money she will end up earning in interest on the cd. (5 points: part i – 1 point; part ii – 1 point; part iii – 1 point; part iv – 1 point; part v – 1 point)
Mathematics
1 answer:
katrin2010 [14]3 years ago
4 0
The formula for getting the accumulated amount(compounded) is;
A =P(1+r%)∧n
Where A = Acumulated amount 
            P = principle (deposit)
            r = interest rate and
            n = period
Since the interst is compounded quartly, 
period = (5×4)-3 = 17

A = 7100(1+2.8/100)∧17
   = 7100×1.028∧17
   = 11,353.80

The money she will end up earning in interest on the cd = $11,353.80
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Debora [2.8K]

Step-by-step explanation:

Selling Price (SP) = Rs. 725

profit rate (P%) = 15 %

Now

Cost Price (CP)

=  \frac{sp \:  \times 100}{100 + p\%}  \\  =  \frac{725 \times 100}{100 + 15}   \\  =  \frac{72500}{115}  \\  = rs \: 630.42

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3 years ago
If f(x)=3x^3 then what is the area enclosed by the graph of the function, the horizontal axis, and vertical lines at x=2 and x=4
Ber [7]

Answer:

Area: 180 units2 (units 2 is because since the are no specific unit given but every area should have a unit  of measurement)

Step-by-step explanation:

The area enclosed by the graph of the function, the horizontal axis, and vertical lines is the integral of the function between thos two points (x=2 and x=4)

So , let's solve the integral of f(x)

Area =\int\limits^2_4 3{x}^3 \, dx = 3*x^4/4+C

C=0

So if we evaluate this function in the given segment:

Area= 3* (4^4)/4-3*(2^4)/4= 3*(4^4-2^4)/4=180 units 2

Goos luck!

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2 years ago
Zachary and his children went into a bakery and he bought $15 worth of cupcakes and brownies. Each cupcake costs $3 and each bro
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Step-by-step explanation:

the answer is

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3 years ago
Read 2 more answers
The American Association of Individual Investors conducts a weekly survey of its members to measure the percent who are bullish,
vredina [299]

Answer:

1. There is not enough evidence to support the claim that bullish sentiment differs from its long-term average of 0.39.

2. There is enough evidence to support the claim that bearish sentiment is above its long-term average of 0.30.

Step-by-step explanation:

The question is incomplete:

The American Association of Individual Investors conducts a weekly survey of its members to measure the percent who are bullish, bearish, and neutral on the stock market for the next six months. For the week ending November 7, 2012 the survey results showed 38.5% bullish, 21.6% neutral, and 39.9% bearish (AAII website, November 12, 2012). Assume these results are based on a sample of 300 AAII members.

1. This is a hypothesis test for a proportion.

The claim is that bullish sentiment differs from its long-term average of 0.39.

Then, the null and alternative hypothesis are:

H_0: \pi=0.39\\\\H_a:\pi\neq 0.39

The significance level is 0.05.

The sample has a size n=300.

The sample proportion is p=0.385.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.39*0.61}{300}}\\\\\\ \sigma_p=\sqrt{0.000793}=0.028

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.385-0.39+0.5/300}{0.028}=\dfrac{-0.003}{0.028}=-0.118

This test is a two-tailed test, so the P-value for this test is calculated as:

P-value=2\cdot P(z

As the P-value (0.906) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that bullish sentiment differs from its long-term average of 0.39.

2) This is a hypothesis test for a proportion.

The claim is that bearish sentiment is above its long-term average of 0.30.

Then, the null and alternative hypothesis are:

H_0: \pi=0.3\\\\H_a:\pi\neq 0.3

The significance level is 0.05.

The sample has a size n=300.

The sample proportion is p=0.399.

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.3*0.7}{300}}\\\\\\ \sigma_p=\sqrt{0.0007}=0.026

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.399-0.3-0.5/300}{0.026}=\dfrac{0.097}{0.026}=3.679

This test is a two-tailed test, so the P-value for this test is calculated as:

P-value=2\cdot P(z>3.679)=0

As the P-value (0) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that bearish sentiment is above its long-term average of 0.30.

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3 years ago
Why is 8.8 classified as a rational number?
hichkok12 [17]
A rational number can be expressed as the ratio of two integers.

\frac{a}{b}

Where a and b are integers and b is not equal to 0.

The rational number 8.8 can be expressed as two integers. Like \frac{8.8}{1}
4 0
3 years ago
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