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Thepotemich [5.8K]
3 years ago
7

Help me pleaseeeee.

Mathematics
1 answer:
Natali [406]3 years ago
4 0

Answer:

7.) Line, point

8.) Line

9.) Line, point, rotational

10.) Rotational

11.) None

12.) Line

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Find the balance in an account with $4,250 principal earning 3% interest compounded quarterly after 12 years. Round your answer
Marat540 [252]
X = principle ( 1 + rate/compound rate) ^ years

x = 4250[1+(0.3/4)]^12
x = 4250(1+0.075)^12
x = 4250(1.075)^12
x = 4250(2.38178)
x = $10,122.23
3 0
4 years ago
A point in the figure is selected at random find the probability that a point will be in the part that is not selected
Nata [24]

Answer:

about 65 percentage is the correct answer

6 0
3 years ago
Will mixes 1/4 gallon of milk and 1/2 gallon of chocolate syrup to make chocolate milk. Each serving is 1/16 gallon. How many se
Dennis_Churaev [7]

Answer:

12 servings!

Step-by-step explanation:

1/4 equals 0.25 gallons, 1/2 gallons is 0.5, so Will will have a mix of 0.75 gallons. If each serving is 1/16 and 1/16 equals 0.0625, divide 0.75 by 0.0625 = 12 servings.

6 0
3 years ago
Which graph is the graph of y=⌈x⌉ over the domain 3≤x≤6 ?<br><br> (Graphs below)
bezimeni [28]
The bottom right graph is correct. x must fall between 3 and 6, so that automatically rules out the bottom left, as one of the points falls on 2.

the top left is incorrect because it doesn't show that x is greater than or EQUAL to three. it has an open circle rather than a closed circle. that's two answer choices eliminated.

from there, you just have to refer back to your given information:

<span>3≤x≤6

the given info says that x must be between or equal to 3 and 6. the top right graph leaves out a "step" because it has 5 and 6 as solid dots side by side.</span>
6 0
4 years ago
Angle θ is in standard position and (−6,−3) is a point on the terminal side of θ. What is the exact value of csc θ in simplest f
bearhunter [10]

Answer:

\displaystyle \csc\theta=-\frac{\sqrt{5}}{2}

Step-by-step explanation:

Since \displaystyle \csc\theta=\frac{1}{\sin\theta}=\frac{1}{\frac{\text{Opposite}}{\text{Hypotenuse}}}=\frac{\text{Hypotenuse}}{\text{Opposite}}, we need to find the hypotenuse given our corresponding opposite and adjacent lengths of -6 and -3 accounting for Quadrant III:

(-6)^2+(-3)^2=c^2\\\\36+9=c^2\\\\45=c^2\\\\\sqrt{45}=c\\\\c=3\sqrt{5}

Thus, \displaystyle \csc\theta=\frac{\text{Hypotenuse}}{\text{Opposite}}=\frac{3\sqrt{5}}{-6}=-\frac{\sqrt{5}}{2}

4 0
2 years ago
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