Answer:
True Statement are
![\sin E =\dfrac{11}{\sqrt{185}}](https://tex.z-dn.net/?f=%5Csin%20E%20%3D%5Cdfrac%7B11%7D%7B%5Csqrt%7B185%7D%7D)
![\sin D =\dfrac{8}{\sqrt{185}}](https://tex.z-dn.net/?f=%5Csin%20D%20%3D%5Cdfrac%7B8%7D%7B%5Csqrt%7B185%7D%7D)
Step-by-step explanation:
Given:
DF = 11
EF = 8
![DE = \sqrt{185}=Hypotenuse](https://tex.z-dn.net/?f=DE%20%3D%20%5Csqrt%7B185%7D%3DHypotenuse)
In Right Angle Triangle DEF, the Sine Identity is
![\sin D = \dfrac{\textrm{side opposite to angle D}}{Hypotenuse}\\](https://tex.z-dn.net/?f=%5Csin%20D%20%3D%20%5Cdfrac%7B%5Ctextrm%7Bside%20opposite%20to%20angle%20D%7D%7D%7BHypotenuse%7D%5C%5C)
Substituting the values we get
![\sin D = \dfrac{EF}{DE}=\dfrac{8}{\sqrt{185}}](https://tex.z-dn.net/?f=%5Csin%20D%20%3D%20%5Cdfrac%7BEF%7D%7BDE%7D%3D%5Cdfrac%7B8%7D%7B%5Csqrt%7B185%7D%7D)
....True
And also,
![\sin E = \dfrac{\textrm{side opposite to angle E}}{Hypotenuse}\\](https://tex.z-dn.net/?f=%5Csin%20E%20%3D%20%5Cdfrac%7B%5Ctextrm%7Bside%20opposite%20to%20angle%20E%7D%7D%7BHypotenuse%7D%5C%5C)
Substituting the values we get
![\sin E = \dfrac{DF}{DE}=\dfrac{11}{\sqrt{185}}](https://tex.z-dn.net/?f=%5Csin%20E%20%3D%20%5Cdfrac%7BDF%7D%7BDE%7D%3D%5Cdfrac%7B11%7D%7B%5Csqrt%7B185%7D%7D)
....True
Answer:
uhhhh... I'm sorry but idk this one , j hope you find it :)
We can start to solve this problem like how we solve any division problem. Since 8 doesn't go evenly into 4, we can move one digit to right, giving us the number 42. 42 divided by 8 is 5, so we write 5 on top of the division bar and keep working. Since 42-40 is 2, there's still 2 remained after doing that. Now we can bring down the 6, turning the number into 26. 26 divided by 8 is 3 remained 2, so we can put the three next to the 5. Since we have two remained and no more numbers, that means that the answer to 426/8 is 53 remainder 2.
Answer:
7/8
Step-by-step explanation:
take the square root of the top and the square root of the bottom
Answer: 300, the volume is 300 because you take 10 times 5 times 6 and you get the volume