Divide. Give the quotient and remainder. 426÷8

1 answer:

8 0

We can start to solve this problem like how we solve any division problem. Since 8 doesn't go evenly into 4, we can move one digit to right, giving us the number 42. 42 divided by 8 is 5, so we write 5 on top of the division bar and keep working. Since 42-40 is 2, there's still 2 remained after doing that. Now we can bring down the 6, turning the number into 26. 26 divided by 8 is 3 remained 2, so we can put the three next to the 5. Since we have two remained and no more numbers, that means that the answer to 426/8 is 53 remainder 2.

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In a recent survey, 64 % of the community favored building a police substation in their neighborhood. If 14 citizens are chosen,

kozerog [31]

Answer: 0.1840

Step-by-step explanation:

The binomial probability formula :-

$P(X)=^nC_x\ p^x(1-p)^{n-x}$ , here n is the number total of trials , p is the probability of getting success in each trial and P(x) is the probability of getting success in x trial.

Given : The probability of the community favored building a police substation in their neighborhood = 0.64

If 14 citizens are chosen, then the probability that exactly 8 of them favor the building of the police substation will be :-

$P(8)={14}^C_{8}\ (0.64)^{8}(1-0.64)^{14-8}\\\\=\dfrac{14!}{8!6!}\times(0.64)^8(0.36)^{6}\\\\0.183996740126\approx0.1840$

Hence, the probability that exactly 8 of them favor the building of the police substation = 0.1840

5 0

4 years ago

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$