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frozen [14]
4 years ago
6

Select all true statements for the triangle shown.

Mathematics
2 answers:
Mandarinka [93]4 years ago
8 0

Answer:

A and C

Step-by-step explanation:

Just did it on  edge

PIT_PIT [208]4 years ago
4 0

Answer:

True Statement are

\sin E =\dfrac{11}{\sqrt{185}}

\sin D =\dfrac{8}{\sqrt{185}}

Step-by-step explanation:

Given:

DF = 11

EF = 8

DE = \sqrt{185}=Hypotenuse

In Right Angle Triangle DEF, the Sine Identity is

\sin D = \dfrac{\textrm{side opposite to angle D}}{Hypotenuse}\\

Substituting the values we get

\sin D = \dfrac{EF}{DE}=\dfrac{8}{\sqrt{185}}

\sin D =\dfrac{8}{\sqrt{185}} ....True

And also,

\sin E = \dfrac{\textrm{side opposite to angle E}}{Hypotenuse}\\

Substituting the values we get

\sin E = \dfrac{DF}{DE}=\dfrac{11}{\sqrt{185}}

\sin E =\dfrac{11}{\sqrt{185}} ....True

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Oliver runs for 9 more minutes than Bobby.
valentina_108 [34]
The answer is C 24 if you plug in 33 33 = 9 + b you have to subtract the 9 over to 33 to get 24
3 0
3 years ago
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Helpppppppppppp plzzzzzzzzzzzzzzzzzz!
prisoha [69]

Answer: F=140

Step-by-step explanation:

720=(x-60)+(x-40)+(x-20)+130+120+110

720-130-120-110=3x-120

360=3x-120

360+120=3x

480=3x

480/3=x

160=x

F=160-20

Next problem

102+31+x=180

133+x=180

x=180-133

x=47

7 0
3 years ago
What is the area of the composite figure? (use 3.14 for pi). Explain how you arrived at your answer. Please round to the nearest
maksim [4K]

The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

Step-by-step explanation:

The given is,

                 Given diagram is combination of Rectangle and Semi circle.

Step:1

         Res the attachment,

                      Area of given diagram = Area of A + Area of B..............(1)

Step:2

         For A,

         The A section in the given diagram is semi circle,

                     Diameter of semi circle = Total distance - ( 2+3)

                                          ( ∵ 2, 3 are top distance in the given diagram)

                                                             = 10 - 5

                                        Diameter, d = 5 cm

                                             Radius, r = \frac{d}{2}

                                                          r = \frac{5}{2}

                                                         r = 2.5 cm

                                          Area, A_{A}  = \frac {\pi r^{2} }{2}........................(2)

                                                    A_{A}  = \frac {\pi (2.5)^{2} }{2}  

                                                           = \frac {\pi ( 6.25) }{2}

                                                           = \frac{19.63}{2}

                                                     A_{A} = 9.8174 cm^{2}

Step:3

               For B,

               Area of rectangle is,

                                                      A_{B} =lb.....................(3)

              Where, l - Length = 10 cm

                          b - Width = 2 cm

              Equation (3) become,

                                                            = (10)(2)

                                                            = 20

                                    Area of B, A_{B} = 20 cm^{2}

Step:4

               From the equation (1),

                               Area of given diagram = 20+ 9.81747

                                                            Area = 29.817 square centimeters

Result:

            The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

5 0
3 years ago
Write the following as an inequality
Ipatiy [6.2K]

Answer:

3 ≤ w ≤ 4

Step-by-step explanation:

the statements are 3 ≤ w  and 4 ≥ w ( or w ≤ 4 )

These can be combined into the single inequality

3 ≤ w ≤ 4


4 0
3 years ago
Find m∠1 and m∠3 in the kite. The diagram is not drawn to scale.
Alex_Xolod [135]

Answer:

m<1 = 39°

m<3 = 180-90-39= 51°

Step-by-step explanation:

Lines AC and DB are diagonals and always meet at right angles.

Kites have two sets of equivalent adjacent sides and one set up of congruent opposite angles.

3 0
3 years ago
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