All categories

3 years ago

To solve for y in the equation 2 x + y = 5, subtract 2 from both sides of the equation.

Mathematics

2 answers:

torisob [31]3 years ago

5 0

Answer:

False

Step-by-step explanation:

To solve this equation 2x + y = 5, you need another pair equation with the same variables, or one of the variables (x or y) need to be known to solve this equation.

Or you need to subtract 2x from both side to make y subject of formula.

steposvetlana [31]3 years ago

3 0

Answer:

False.

Step-by-step explanation:

Because we have to isolate y and subtracting 2 will not put y alone on one side.

We have to subtract 2x in order to solve for y.

You might be interested in

PLEASE HELP

Lostsunrise [7]

Answer:

is there a visual version of this question?

3 0

3 years ago

Read 2 more answers

Options for awnser is a,b,c,d

Aleks04 [339]

Answer:

Step-by-step explanation:

______

Good evening ,

_______________

The right answer is D

We should rotate the R point 3/4 a circle clockwise so it falls on D point.

8 0

4 years ago

Read 2 more answers

Which mixed number is greater than 6.78?

Crazy boy [7]

I thinks it's D, due to the process elimination

6 0

4 years ago

Read 2 more answers

Which of the following is the complete list of roots for the polynomial function f(x)=(x^2+6x+8)(x^2+6x+13)

MrMuchimi

Answer:

Step-by-step explanation:

$f(x)=(x^2+6x+8)(x^2+6x+13)\\\\f(x)=0\iff(x^2+6x+8)(x^2+6x+13)=0\iff\\x^2+6x+8=0\vee x^2+6x+13=0\\\\x^2+6x+8=0\\x^2+4x+2x+8=0\\x(x+4)+2(x+4)=0\\(x+4)(x+2)=0\iff x+4=0\ \vee\ x+2=0\\x+4=0\qquad\text{subtract 4 from both sides}\\\boxed{x=-4}\\x+2=0\qquad\text{subtract 2 from both sides}\\\boxed{x=-2}\\\\x^2+6x+13=0\qquad\text{subtract 13 from both sides}\\x^2+6x=-13\\x^2+2(x)(3)=-13\qquad\text{add}\ 3^2=9\ \text{to both sides}\\x^2+2(x)(3)+3^2=-13+9\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\(x+3)^2=-4$

8 0

3 years ago

I need help on this question

barxatty [35]

I believe this is pythag

15^2 x 11^2 = 27225

(square root) of 27225 = 165

165ft

6 0

3 years ago