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3 years ago

To solve for y in the equation 2 x + y = 5, subtract 2 from both sides of the equation.

Mathematics

2 answers:

torisob [31]3 years ago

5 0

Answer:

False

Step-by-step explanation:

To solve this equation 2x + y = 5, you need another pair equation with the same variables, or one of the variables (x or y) need to be known to solve this equation.

Or you need to subtract 2x from both side to make y subject of formula.

steposvetlana [31]3 years ago

3 0

Answer:

False.

Step-by-step explanation:

Because we have to isolate y and subtracting 2 will not put y alone on one side.

We have to subtract 2x in order to solve for y.

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Find the magnitude of WX for W(-2, 8, -3) and X(1, 4, -1)

zheka24 [161]

The magnitude of WX is $\sqrt{29}$ ⇒ c

Step-by-step explanation:

The magnitude of XY (its length) where,

$X=(x_{1},y_{1},z_{1})$
$Y=(x_{2},y_{2},z_{2})$

is IXYI = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}$

∵ W = (-2 , 8 , -3)

∵ X = (1 , 4 , -1)

- To find the magnitude of WX use the formula above

∴ $x_{1}$ = -2 and $x_{2}$ = 1

∴ $y_{1}$ = 8 and $y_{2}$ = 4

∴ $z_{1}$ = -3 and $z_{2]$ = -1

- Substitute these values in the rule above

∵ IWXI = $\sqrt{(1--2)^{2}+(4-8)^{2}+(-1--3)^{2}}=\sqrt{9+16+4}$

∴ IWXI = $\sqrt{29}$

The magnitude of WX is $\sqrt{29}$

Learn more:

You can learn more about the position of an object in brainly.com/question/10940255

#LearnwithBrainly

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