<span>Hello there.
</span><span>Factor x^3 2x^2-29x-30
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This on is very easy go to my website so i can explain it better for you
<span>https://www.youtube.com/channel/UCaxhPMTZBmFcxAZ4hYpBf_w
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Hope this
X=3
y=5
You have to cancel out either the x values or the y values (I chose y). You multiply both equations by particular numbers so either the x values or y values can be equal to each other, as well as positive or negative to each other. I multiplied -7y by 4 and 4y by 7, and got -28y and 28y. I then canceled those out. The numbers you multiply by also affects the rest of the equations, so I ended up with 48x=4 and -35x=35. After that, you combine like terms, which results in 13x=39. You divide 13 by both sides and you end up with x=3. To find y, all you have to do is plug in the x value to one of the equations, then solve for y. I resulted in y=5.
Hope this helped ^_^
A) ![\sqrt[3]{x^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E4%7D)
B) Decimal Form:
0.87358046
sorry if i didnt get the 2nd one right i tired tho
mark brailiest please
:)
Answer:
the answer is 1/12
Step-by-step explanation:
it is 1/12 because if there are only a pair you would have 2 dice. and since each die has numbers all the way up to 6 all you have to do is add them. and don't count all the numbers. like add 1+2+3+4+5+6. that's just plain wrong just do add the highest number on each die (6+6)
