Ask question

Ask question

All categories

3 years ago

8

Factor completly 108-3x^2

1 answer:

Sergeu [11.5K]3 years ago

3 0

The fully factored polynomial is −3(x−6)(x+6).

You might be interested in

What is 7+78/3=?<br> A.43<br> B.25<br> C.25.5<br> D.75

Andrei [34K]

So correct answer is 33

6 0

3 years ago

Select the correct answer. Twenty students in Class A and 20 students in Class B were asked how many hours they took to prepare

Lunna [17]

Answer:

B: The mean study time of students in Class B is less than students in Class A.

Step-by-step explanation:

To find out why answer B is the right answer, I will give you facts from each option.

Option A is false. <em>The mean study time in Class A is 4.8. Meanwhile in Class B it is 4. For Class A, sum up the 20 study times which is 96 and divide them by 20, you will get 4.8 hours of mean study time. For Class B, the sum of the 20 study times is 80, which divided by 20 will be 4. </em>

Option B is True. <em>See previous explanation. </em>

Option C is False. <em>The median study time in Class B is 4. The median study time in Class A is 4.8, </em>

Option D is False. <em>The range in Class A is from 2 to 8. The range in Class B is from 2 to 7. </em>

Option E is False: <em>The mean and median study time of these classes is different.</em>

6 0

3 years ago

Read 2 more answers

A is an m×n matrix.Check the true statements below:A. The kernel of a linear transformation is a vector space.B. If the equation

Bess [88]

Answer:

Results are (1) True. (2) False. (3) False. (4) True. (5) True. (6) True.

Step-by-step explanation:

Given A is an $m\times n$ matrix. Let $T :U\to V$ be the corresponding linear transformationover the field F and $\theta$ be identity vector in V. Now if $x\in Ker( T)\implies T(x)=\theta$ .

(1) The kernel of a linear transformation is a vector space : True.

Let $x,y\in Ker( T)$ , then,

$T(x+y)=T(x)+T(y)=\theta+\theta=\theta\impies x+y\in Ker( T)$

hence the kernel is closed under addition.

Let $\lambda\in F, x\in Ker( T)$ , then

$T(\lambda x)=\lambda T(x)=\lambda\times \theta=\theta$

$\lambda x\in Ker(T)$ and thus Ket(T) is closed under multiplication

Finally, fore all vectors $u\in U$ ,

$T(\theta)=T(\theta+(-\theta))=T(\theta)+T(-\theta)=T(\theta)-T(\theta)=\theta$

$\implies \theta\in Ker(T)$

Thus Ker(T) is a subspace.

(2) If the equation Ax=b is consistent, then Col(A) is $\mathbb R^m$ : False

if the equation Ax=b is consistent, then Col(A) must be consistent for all b.

(3) The null space of an mxn matrix is in $\mathbb R^m$

: False

The null space that is dimension of solution space of an m x n matrix is always in $\mathbb R^n$ .

(4) The column space of A is the range of the mapping $x\to Ax$

: True.

(5) Col(A) is the set of all vectors that can be written as Ax for some x. : True.

Here Ax will give a linear combination of column of A as a weights of x.

(6) The null space of A is the solution set of the equation Ax=0.

: True

5 0

3 years ago

Is 3 squared times 4 squared equal 12 squared ? Evaluate each side of the equation to explain your answer.

Nikolay [14]

Answer:

Nopes 3²+4²≠12²

Step-by-step explanation:

12²=144

3²+4²=

9+16=25

25≠144

To make it easier to see exactly WHY 3²+4²≠12² you can spread out the numbers in the equation.

(3·3)+(4·4)≠(12·12)

When solving equations you use PEMDAS (Parenthesis Exponents Multiplication Division Addition Subtraction). You have to solve in THAT ORDER.

7 0

3 years ago

Read 2 more answers

In order to make an A on her project, Sarah needs at least 160 points. She has already turned in part of her work and has been g

antoniya [11.8K]

to get an A, she needs >=160 points and she already has 125 points

let 'x' be the number of points on the last part of her project then

125 + x >= 160

x >= 160 - 125

x >= 35

Sarah needs at least 35 points on the last part of her project.

8 0

3 years ago

Read 2 more answers