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Mashutka [201]
4 years ago
12

Solve uThanksI don't know it​

Mathematics
1 answer:
zavuch27 [327]4 years ago
5 0

Step-by-step explanation:

With reference angle 60°

perpendicular (p) = u

base (b) = 5 mm

Now

tan 60° = p / b

√3 = u / 5

Now cross multiply

u = 5√3 mm

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Help please also dont put links:(​
Zepler [3.9K]

Answer:  $61.50

Step-by-step explanation:

To do this you need to first find 18% of 75 which is 13.5 or $13.50 and then subtract that from the original price being $75 and you get $61.50

HOPE THIS HELPS ^^

3 0
3 years ago
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you are in line at an amusement park. You count 34 people in front of you. Each rollercoaster fits 11 people. How many rollercoa
rewona [7]
3 because you are next in line
5 0
4 years ago
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Name two properties used to evaluate 7x1-4x1/4
Kitty [74]
7x1=7, then 4x1/4= 4x1=4 divided by 4= 1. Then subtract 7- 1= 6
5 0
3 years ago
What is the value of x
mylen [45]

Answer:

x<-19    

Step-by-step explanation:

hope that helps

5 0
3 years ago
colby and jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the num
kaheart [24]
To get started, we will use the general formula for bacteria growth/decay problems:

A_{f} =  A_{i} ( e^{kt} )

where: 
A_{f} = Final amount
A_{i} = Initial amount
k = growth rate constant
t = time


For doubling problems, the general formula can be shortened to:

kt = ln(2)

Now, we can use the shortened formula to calculate the growth rate constant of both bacteria:

Colby (1):
k_{1} = ln(2)/t
k_{1} = ln(2)/2 = 0.34657 per hour

Jaquan (2):
k_{2} = ln(2)/t
k_{2} = ln(2)/3 = 0.23105 per hour

Using Colby's rate constant, we can use the general formula to calculate for Colby's final amount after 1 day (24 hours).

Note: All units must be constant, so convert day to hours.

A_{f1} = 50( e^{0.34657(24)})
A_{f1} = 204,800

Remember that the final amount for both bacteria must be the same after 24 hours. Again, using the general formula, we can calculate the initial amount of bacteria that Jaquan needs:

A_{f2} = 204,800 =  A_{i2} ( e^{0.23105(24)} )
A_{i2} = 800

3 0
3 years ago
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