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mihalych1998 [28]

2 years ago

7

Graph the system of inequalities. Then state whether the situation is infeasible, has alternate optimal solutions, or is unbound

ed. (Assume that x>0 y>0

1 answer:

shtirl [24]2 years ago

5 0

Answer:

x

$x \leqslant - y + 1$

Steps are show in the picture above.

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Choose the equation of the horizontel line that passes through the point (-2,-1)

vitfil [10]

Answer:

y = -1

Step-by-step explanation:

A horizontal line is of the form

y =

The y coordinate of the point (-2,-1) is -1

The equation is y = -1

8 0

2 years ago

sam goes to lunch with a friend. the total cost of the lunch is $15 . sam leaves $1.50 as a tip. what percent of total did he ti

gavmur [86]

It should be a 10% tip. To simplify the answer, The decimal moves one space (which would be equal to a tenth) so it’s a 10%

7 0

3 years ago

36 is _______% less than 60?

Arte-miy333 [17]

60*(1-x)=36
60-60x=36
-60x=36-60
-60x=-24
x=24/60
x=4/10
x=2/5
x=0.4

36 is 40% less than 60

4 0

3 years ago

Read 2 more answers

The vertices of a triangle ABC are A(7, 5), B(4, 2), and C(9, 2). What is measure of angle ABC? 30° 45° 56.31° 78.69°

GenaCL600 [577]

The measure of angle ABC is 45°

<em><u>Explanation</u></em>

Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)

According to the diagram below....

Length of the side BC (a) $=\sqrt{(4-9)^2+(2-2)^2}= \sqrt{25}= 5$

Length of the side AC (b) $= \sqrt{(7-9)^2 +(5-2)^2}= \sqrt{4+9}=\sqrt{13}$

Length of the side AB (c) $= \sqrt{(7-4)^2 +(5-2)^2} =\sqrt{9+9}=\sqrt{18}$

We need to find ∠ABC or ∠B . So using <u>Cosine rule</u>, we will get...

$cosB= \frac{a^2+c^2-b^2}{2ac} \\ \\ cos B= \frac{(5)^2+(\sqrt{18})^2-(\sqrt{13})^2}{2*5*\sqrt{18} }\\ \\ cosB= \frac{25+18-13}{10\sqrt{18}} =\frac{30}{10\sqrt{18}}=\frac{3}{\sqrt{18}}\\ \\ cosB=\frac{3}{3\sqrt{2}} =\frac{1}{\sqrt{2}}\\ \\ B= cos^-^1(\frac{1}{\sqrt{2}})= 45 degree$

So, the measure of angle ABC is 45°

7 0

3 years ago

Read 2 more answers

Graph. y−2=2/3(x+4) Use the Line Tool and select two points to graph the equation. Use the slope and the point provided in the e

Darya [45]

Based on the equation, the coordinate point is (-4, 2). It is -4 because in the original equation, it's $-x_{1}$ , but because it's positive, that must mean it was originally a negative. Why? Because a negative times an negative equals a positive.

Now, let's convert this to Slope-Intercept Form.

y - 2 = 2/3(x + 4)
y - 2 = 2/3x + 8/3
Add 2 to both sides.
y = 2/3x + 14/3

The slope of the line is 2/3 and the original point was (-4, 2).

6 0

3 years ago