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3 years ago

What percent is the change in the price if the price was $100 and now it is $1250?

Mathematics

2 answers:

Vsevolod [243]3 years ago

6 0

Answer:

1150%

Step-by-step explanation:

The percentage change is ...

percentage change = (amount of change)/(original amount) × 100%

= ((new amount) - (original amount))/(original amount) × 100%

= ($1250 -$100)/$100 × 100%

= 1150/100 × 100%

= 1150%

WINSTONCH [101]3 years ago

4 0

Answer: 1150%

Step-by-step explanation: To calculate the percentage increase in price we apply the formula:

Percentage change = [100 (New selling price/cost - Old price/cost)] / 100

New cost = $1250

Old cost = $100

Therefore, percentage change = [100 (1250 - 100)] / 100

(100 x 1150) / 100 = 1150%

Price increased by 1150% from $100 to $1250.

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An English professor assigns letter grades on a test according to the following scheme. A: Top 9% of scores B: Scores below the

sergeinik [125]

Answer:

The minimum score required for an A grade is 83.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 72.3 and a standard deviation of 8.

This means that $\mu = 72.3, \sigma = 8$

Find the minimum score required for an A grade.

This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.

$Z = \frac{X - \mu}{\sigma}$

$1.34 = \frac{X - 72.3}{8}$

$X - 72.3 = 1.34*8$

$X = 83$

The minimum score required for an A grade is 83.

5 0

3 years ago

Factor out the coefficient of the variable -3.6m + 10.8

MA_775_DIABLO [31]

Answer: -1

Step-by-step explanation: First, factor out 3.6. You should get -m+3. Since the coefficient is just the number being multiplied to the variable (which is m here), your coefficient should be -1 because m is being multiplied to -1 to make -m. Hope this helps!

3 0

3 years ago

Answer 6s^5t x s^4t^2

babunello [35]

Answer:

6s⁹t³

Step-by-step explanation:

6s⁵t ₓ s⁴t² =

= 6ₓs⁵⁺⁴t¹⁺²

= 6s⁹t³

8 0

3 years ago

Read 2 more answers

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.