What percent is the change in the price if the price was $100 and now it is $1250?

Mathematics

2 answers:

Vsevolod [243]2 years ago

6 0

Answer:

1150%

Step-by-step explanation:

The percentage change is ...

percentage change = (amount of change)/(original amount) × 100%

= ((new amount) - (original amount))/(original amount) × 100%

= ($1250 -$100)/$100 × 100%

= 1150/100 × 100%

= 1150%

WINSTONCH [101]2 years ago

4 0

Answer: 1150%

Step-by-step explanation: To calculate the percentage increase in price we apply the formula:

Percentage change = [100 (New selling price/cost - Old price/cost)] / 100

New cost = $1250

Old cost = $100

Therefore, percentage change = [100 (1250 - 100)] / 100

(100 x 1150) / 100 = 1150%

Price increased by 1150% from $100 to $1250.

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This is solving differential equations by sepeartion of variables

Brums [2.3K]

$\mathrm dy+k(y-70)\,\mathrm dx=0$

Separating variables gives

$\dfrac{\mathrm dy}{y-70}=-k\,\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dy}{y-70}=-k\int\mathrm dx$
$\ln|y-70|+C_1=-kx+C_2$
$\ln|y-70|=-kx+C$

Solving for $y$ gives

$e^{\ln|y-70|}=e^{-kx+C}$
$y-70=e^{-kx}e^C$
$y=Ce^{-kx}+70$

As $y(1)=140$ , you get

$140=Ce^{-k}+70$
$70=Ce^{-k}$
$C=70e^k$

so the particular solution to this ODE is

$y=70e^ke^{-kx}+70$
$y=70e^{k(1-x)}+70$

Unless you have any more information, you're done.

5 0

2 years ago

50 points and brainliest!

lora16 [44]

Answer:

Step-by-step explanation:

$\frac{27^{1/3b}}{9^{1/2a}}$