Let
be the length of the rectangle and
be the width. In the problem it is given that
. It is also given that the area
. Substituting in the length in terms of width, we have
. Using the zero product property,
. Solving these we get the width
. However, it doesn't make sense for the width to be negative, so the width must be
. From that we can tell the length
.
$288.75 I believe! Sorry if my answer is incorrect!
I cannot see the text. If you take another picture zoomed in I will answer it.
Distribute. 32-4x+36=92-6x-48 Then add common factors. 68-4x=44-6x Get the x's on one side. 24=-2x Divide by -2. -12=x is your answer
if you use the desmos graphing calculator - since you didn't provide answer choices - it should be able to help you.