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Dennis_Churaev [7]
3 years ago
7

Help me please this should be easy ​

Mathematics
1 answer:
vichka [17]3 years ago
3 0

Answer:

what grade are you in ?

Step-by-step explanation:

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It is known that there only is 1% chance of getting a disease. a test is being devised to detect the disease. the probability th
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Suppose D is the event that a given patient has the disease, and P is the event of a positive test result.

We're given that

\mathbb P(D)=0.01
\mathbb P(P\mid D)=0.98
\mathbb P(P^C\mid D^C)=0.95

where A^C denotes the complement of an event A.

a. We want to find \mathbb P(P^C). By the law of total probability, we have

\mathbb P(P^C)=\mathbb P(P^C\cap D)+\mathbb P(P^C\cap D^C)

That is, in order for P^C to occur, it must be the case that either D also occurs, or D^C does. Then from the definition of conditional probability we expand this as

\mathbb P(P^C)=\mathbb P(D)\mathbb P(P^C\mid D)+\mathbb P(D^C)\mathbb P(P^C\mid D^C)

so we get

\mathbb P(P^C)=0.01\cdot0.02+0.99\cdot0.95=0.9407

b. We want to find \mathbb P(D\mid P). Now, we can use Bayes' rule, but if you're like me and you find the formula a bit harder to remember, we can easily derive it.

By the definition of conditional probability,

\mathbb P(D\mid P)=\dfrac{\mathbb P(D\cap P)}{\mathbb P(P)}

We have the probabilities of P/P^C occurring given that D/D^C occurs, but not vice versa. However, we can expand the probability in the numerator to get a probability in terms of P being conditioned on D:

\mathbb P(D\cap P)=\mathbb P(D)\mathbb P(P\mid D)

Meanwhile, the law of total probability lets us rewrite the denominator as

\mathbb P(P)=\mathbb P(P\cap D)+\mathbb P(P\cap D^C)

or in terms of conditional probabilities,

\mathbb P(P)=\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)

so that

\mathbb P(D\mid P)=\dfrac{\mathbb P(D)\mathbb P(P\mid D)}{\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)}

which is exactly what Bayes' rule states. So we get

\mathbb P(D\mid P)=\dfrac{0.01\cdot0.98}{0.01\cdot0.98+0.99\cdot0.05}\approx0.1653
6 0
3 years ago
Lisa has developed a new product, and knows that the graph of function R models her revenue from selling the item, after deducti
Eva8 [605]

Answer:

Choice B is correct;  (10, 60)

Step-by-step explanation:

For Lisa to make a profit, the function R should assume a value greater than 0;

R > 0

We are to determine the interval of x values for which the above expression will be true.

From the graph, R(x) = 0 when x = 10. As x increases from 10 to 60, the value of R(x) remains positive, that is;

R(x) ≥ 0 for values of x in the interval (10, 60)

The domain that she should use in order to only model selling prices for which she will make a profit is thus;

(10, 60)

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4 years ago
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The property taxes on a home varies directly with the value of the home. Jack currently lives in a home worth $172,000 and pays
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Okay, where is your question?
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HELP DUE IN 20 MINS!<br><br><br>m∠c =?? degrees<br><br><br>° m∠d =?? degrees
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<c = 45°

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I am not sure okay....this ia sq right?

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Solve the equation by taking the square root 4(x+1)^2=100
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Answer:

Step-by-step explanation:

4(x+1)²=100

(x+1)²= 5²

(x+1)²- 5² = 0

(x+1-5)(x+1+5) = 0  by identity : a² - b ² = (a - b) (a+b)

(x - 4 ) (x+6) =0

x - 4 = 0 or x+6 = 0

x = 4  or x = - 6

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3 years ago
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