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olya-2409 [2.1K]
3 years ago
11

Which step in the solution contains the first error ?? Please helpp

Mathematics
2 answers:
kumpel [21]3 years ago
6 0

Answer:

step 4 I believe

Step-by-step explanation:

dsp733 years ago
3 0
The step in the solution that contains the first error is step 4
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Simplify the following question
fiasKO [112]

Answer:

<em>−  2sin(b) / cos(2b)</em>

​

Step-by-step explanation:

DIFFERENTIATE W.R.T. B is a different method entirely

We simply add together the numerators and set with 2cos

then keep this number and add to sinb and square it.

then repeat initial 2 + cosb ^2 but instead of multiplying its add.

Then set the whole division to -sin (2b) squared then +1

<em> −  2cos(b)(3(sin(b))^2+(cos(b))^2)  /  −(sin(2b)) ^2 +1  </em>

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5 0
2 years ago
A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-­‐
cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics =  4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0
3 years ago
What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?
Akimi4 [234]
\bf \begin{array}{llccll}&#10;term&value\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;a_1&-4096\\&#10;a_2&-4096r\\&#10;a_3&-4096rr\\&#10;a_4&-4096rrr\\&#10;&-4096r^3\\&#10;&64&#10;\end{array}\implies -4096r^3=64&#10;\\\\\\&#10;r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}&#10;\\\\\\&#10;r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\&#10;-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1\cdot r^{n-1}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;r=-\frac{1}{4}\\&#10;a_1=-4096\\&#10;n=6&#10;\end{cases}&#10;\\\\\\&#10;a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
4 0
3 years ago
Read 2 more answers
Find the measure of the angle indicated in bold
Brums [2.3K]

Answer:

d

Step-by-step explanation:

7 0
3 years ago
Tell what whole number you can substitute for A in each list so the numbers are ordered from least to greatest. If there is none
hodyreva [135]

Answer: None

Step-by-step explanation:

If A=4, say for example, our list becomes: 3/4, 4/5, 75%.

This in decimal form becomes: 0.75, 0.8, 0.75 which is clearly not in ascending order.

If A =5, the list becomes 3/5, 5/5, 75% which clearly is 0.6, 1, 0.75 which is also not in ascending order.

For any value of A greater than 5, the second term A/5 is greater than 1 thus being less than the third term 0.75.

Therefore there is no whole number A that makes the list true.

4 0
3 years ago
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